Solution:
![Z score =\frac{X-\sigma}{\mu}](https://tex.z-dn.net/?f=Z%20score%20%3D%5Cfrac%7BX-%5Csigma%7D%7B%5Cmu%7D)
1. For Best Actor
= 59 years
![\sigma=7.3, \mu=42.0](https://tex.z-dn.net/?f=%5Csigma%3D7.3%2C%20%5Cmu%3D42.0)
Z, Score for best actor named, ![Z_{1}](https://tex.z-dn.net/?f=Z_%7B1%7D)
![Z_{1}=\frac{59-7.3}{42}\\\\Z_{1}= \frac{51.7}{42}\\\\Z_{1}=1.23095\\\\ Z_{1}=1.24](https://tex.z-dn.net/?f=Z_%7B1%7D%3D%5Cfrac%7B59-7.3%7D%7B42%7D%5C%5C%5C%5CZ_%7B1%7D%3D%20%5Cfrac%7B51.7%7D%7B42%7D%5C%5C%5C%5CZ_%7B1%7D%3D1.23095%5C%5C%5C%5C%20Z_%7B1%7D%3D1.24)
Z-Score for best actor = 1.24
2. Z , Score for best supporting actor , called ![Z_{2}](https://tex.z-dn.net/?f=Z_%7B2%7D)
=49 years
![\sigma=15, \mu=49.0](https://tex.z-dn.net/?f=%5Csigma%3D15%2C%20%5Cmu%3D49.0)
Z-Score for best supporting actor = 0.70
Z-Score is usually , the number of standard deviations from the mean a point in the data set is.
3. As, ![Z_{1}=1.24](https://tex.z-dn.net/?f=Z_%7B1%7D%3D1.24)
So, we can say that,Option (B) The Best Actor was more than 1 standard deviation above is not unusual.
4.As, ![Z_{2}=0.70](https://tex.z-dn.net/?f=Z_%7B2%7D%3D0.70)
So, we can say that,Option(A) The Best Supporting Actor was less than 1 standard deviation below, is not unusual.
You would circle the 3 in 31, the 9 in 94, and the 1 in 17
Answer:
slope = - ![\frac{5}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B7%7D)
Step-by-step explanation:
Calculate the slope m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 3, 4) and (x₂, y₂ ) = (4, - 1)
m =
= - ![\frac{5}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B7%7D)
Yesssssssss, with what though