<em>Answer:</em>
<em>a is greater than 1, so a−1 is positive.</em>
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<em>The distance between a and 1 appears to be less than the distance between 1 and 0, so it looks like a is less than 2. Thus a−2 is negative.</em>
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<em>b is negative, so −b is positive.</em>
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<em>The distance between a and 0 appears to be less than the distance between b and 0, so it looks like |a| is less than |b|. Since b is negative and a is positive, a+b is negative.</em>
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<em>a−b = a+−b. Since b is negative, −b is positive. a is also positive. Thus, a−b is positive.</em>
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<em>Since |a| and |b| are both greater than 1, |ab| is also greater than 1 (this builds on the intuition students gained in fifth grade as in 5.NF.5). ab is negative since a is positive and b is negative. Thus, ab+1 is negative.</em>
||a|| is called the norm of a. The answer is square root of 58. Hope it helps
Step-by-step explanation:
Taking any two points through which the line passes;(-10,-3) and (-5,-1)
The equation of the line is given by
=> 5y+15 = 2x+20
=> 5y =2x+5
option C
Y = (-2x +2)^2 +8
(-2x^2 +4) +8
-2x^2 +12
Answer: x = 16
Step-by-step explanation:
If RQ is the bisector, that means the angle is cut in half. Therefore angles PRQ and QRS are equal to each other.
4x+6 = 7x-42
subtract 7x from both sides
-3x+6 = -42
subtract 6 from both sides
-3x = -48
divide both sides by -3
x = 16
