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kykrilka [37]
2 years ago
11

In6) which device can not be sharednetwork?​

Computers and Technology
1 answer:
SCORPION-xisa [38]2 years ago
6 0

Answer:

mouse cannot be shared on network

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The company generates a lot of revenue and is rapidly growing. They're expecting to hire hundreds of new employees in the next y
uysha [10]

Answer:

The most appropriate way to deal with the situation presented above is to acquire more space at the current office site at additional rent beforehand.

Explanation:

The Scaling of a revenue-generating business is a crucial task in which a lot of pre-planning and thinking is required.

In order to scale the business in the next year, the planning of it is to be carried out at the moment and proper necessary arrangements are ensured. These steps could be one from:

  • Looking for bigger spaces for renting for a full shift of the operations
  • Looking for a site office for an additional office
  • Acquiring more space in the current office site.

This process would result in acquiring a bigger place beforehand but in order to mitigate the risk, try to keep the place in view by providing them a bare minimum advance for the additional units.

8 0
3 years ago
A hard drive cannot be partitioned until the device _________ is set.
Elza [17]
Partition(ed) is the answer
8 0
3 years ago
Read 2 more answers
How can you tell the value of a purchase?
ZanzabumX [31]
Look at the price tag
find the item on ebay to see what other are selling it for


8 0
2 years ago
Write a recursive function that takes a non-negative integer as an argument and displays the same number in reverse order (i.e.
avanturin [10]

Answer:

Following are the program in C++ language

#include<iostream> // header file

using namespace std; // namespace std

int reverse(int n1); // function prototype

int main()  // main function()

{

   int num; // Variable declaration

   cout << "Enter the number" << endl;

   cin >> num; // Read the number bu the user

  cout<<"After Reverse the digit:\n";

   int res= reverse(num); // calling function reverse

   

   cout<<res; // display  

}

int reverse(int n1) // function definition of reverse

{

   if (n1<10)  // checking the base condition

       {

           return n1;

       }

   else

       {

           cout << n1 % 10; // Printed the last digit

          return reverse(n1/10); // calling itsself

}

}

Output:

Enter the number:

76538

After Reverse the digit:

83567

Explanation:

Following are the description of the program

  • In the main function read the number by user in the "num" variable of int type.
  • Calling the reverse and pass that "num" variable into it.
  • After calling the control moves to the body of the reverse function.In this function we check the two condition

        1  base condition

   if (n1<10)  // checking the base condition

       {

           return n1;

     }

      2  General condition

  else

       {

           cout << n1 % 10; // Printed the last digit

          return reverse(n1/10); // calling itsself

       }

  • Finally return the reverse number and display them into the main function.
5 0
3 years ago
Write a program that simulates flipping a coin repeatedly and continues until three consecutive heads. are tossed. At that point
quester [9]

Answer and Explanation:

#include <iostream>

#include <string>

#include <time.h>

#include <vector>

using namespace std;

//Takes user info

int user_info(string *name,char *gender){

   char G;

   cout<<"What is your name?: ";

   getline(cin, *name);

   cout<<"What is your gender(m/f):";

   cin>>G;

   cout<<endl;

   *gender = tolower(G);

   return 0;

}

//Toss coin(part 2)

bool coin_toss(double seed){

   double r;

   r = (double)seed/(double)RAND_MAX;

   //cout<<r;

   if (r<0.5) return true;

   return false;

}

//check results

float toss_result(vector<char> v,int *h){

   int num_heads=0;

   int num_toss = v.size();

   *h = 0;

   for(int i=0;i<num_toss;i++){

       if(v[i]=='h'){num_heads++;(*h)++;}

   }

   return (float)num_heads/(float)num_toss;

}

void show_result(int total_num,int head_num,float ratio){

   cout<<"it took you "<<total_num<<" tosses to get 3 heads in a row"<<endl;

   cout<<"on average you flipped heads "<<(ratio*100)<<"% of the time"<<endl;

}

int main()

{

   string name;

   char gender;

   string K; //Mr or Mrs

 

   cout<<"Welcome to coin toss! Get 3 heads in row to win!"<<endl;

 

   //part 1

   user_info(&name,&gender);

 

   if(gender == 'f') K = "Mrs.";

   else K = "Mr.";

 

   cout<<"Try to get 3 heads in a row. Good luck "<<K<<name<<"!"<<endl;

   char dummy = getchar();

 

   //part 2

   int num_toss;

   vector<char> toss_results;//store toss results

   bool result;//result of toss

   srand(time(0));

   while(true){

       //cout<<rand()<<endl;

       result = coin_toss(rand());

       cout<<"Press <enter> to flip"<<endl;

       while (1)

       {

           if ('\n' == getchar())

           break;

       }

     

 

     

       if(result) {toss_results.push_back('h');cout<<"HEAD"<<endl;}

       else {toss_results.push_back('t');cout<<"TAIL"<<endl;}

     

       num_toss = toss_results.size();

     

       if(num_toss>=3){

           if ((toss_results[num_toss-1] == 'h')&&(toss_results[num_toss-2] == 'h')&&(toss_results[num_toss-3] == 'h')){

               break;

           }

       }

   }

 

   //part 3

   float ratio_head;

   int num_of_heads;

   ratio_head = toss_result(toss_results,&num_of_heads);

 

   //part 4

 

   show_result(toss_results.size(),num_of_heads,ratio_head);

 

   return 0;

}

8 0
3 years ago
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