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cupoosta [38]
2 years ago
11

A man is five times as old as his son. Four years ago the man was thirteen times as old as his son.

Mathematics
1 answer:
skad [1K]2 years ago
8 0

Answer:

Age of son = 6 years

Age of man = 5×6 = 30 years

Step-by-step explanation:

<u>GIVEN :-</u>

  • A man is 5 times as old as his son. (In Present)
  • 4 years ago , the man was 13 times as old as his son

<u>TO FIND :-</u>

  • The present ages of the man & his son.

<u>SOLUTION :-</u>

Let the present age of son be 'x'.

⇒ Present age of man = 5x

4 years ago ,

Age of son = (Present age of son) - 4 = x - 4

Age of man = (Present age of man) - 4 = 5x - 4

The man was thirteen times as old as his son. So,

=> 5x - 4 = 13(x - 4)

Now , solve the equation.

  • Open the brackets in R.H.S.

=> 5x - 4 = 13x - 52

  • Take 5x to R.H.S. and -52 to L.H.S. Also , take care of their signs because they are getting displaced from L.H.S. to R.H.S. or vice-versa.

=> 13x - 5x = 52 - 4

=> 8x = 48

  • Divide both the sides by 8

=> \frac{8x}{8} = \frac{48}{8}

=> x = 6

<u>CONCLUSION :-</u>

Age of son = 6 years

Age of man = 5×6 = 30 years

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