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Neko [114]
3 years ago
10

A company mixes pecans, cashews, peanuts, and walnuts to make a batch of mixed nuts. About 15.4% of the mixed nuts in a batch ar

e pecans. If a batch contains 77 pounds of pecans, how many pounds of mixed nuts are in a batch altogether? Enter your answer in the box.
Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0

Answer:

500 lb

Step-by-step explanation:

You have to make a proportion:

\frac{part}{whole} = \frac{percent}{100}

77 lb is part of the whole weight ( which we don't know) so 77 will go on top

The problem tells us that 15.4% of the total weight is pecans so 15.4 will go over 100 (since % are out of 100)

\frac{77}{x} = \frac{15.4}{100}

Then you cross multiply giving you: 7700 = 15.4x

then you divide 15.4 to both sides to isolate x which will give you 500

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Assuming that i = 3.14, how much air will it take to fill a sports ball with a radius of 15 inches?
Licemer1 [7]

Answer:

706.86

Step-by-step explanation:

15² x π = 706.86

6 0
3 years ago
Solve the equation or formula for the variable specified 8qr+4t=7u for q ?
g100num [7]

Answer:

q= −4t+7u  over 8r

Step-by-step explanation:

8qr+4t=7u

Step 1: Add -4t to both sides.

8qr+4t+−4t=7u+−4t

8qr=−4t+7u

Step 2: Divide both sides by 8r.

8qr

8r

=

−4t+7u

8r

q=

−4t+7u

8r

Answer:

q=

−4t+7u

8r

4 0
3 years ago
The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it
brilliants [131]

Answer:

(a) 11.25 and 1.68  

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 15

             r = number of success

             p = probability of success which in our question is % of cases in

                  which customer problems are resolved on the same day, i.e.;75%

So, here X ~ Binom(n=15,p=0.75)

(a) Expected number of problems to be resolved today = E(X)

            E(X) = \mu = n * p = 15 * 0.75 = 11.25

    Standard deviation = \sigma = \sqrt{n*p*(1-p)} = \sqrt{15*0.75*(1-0.75)} = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

     P(X = 10) = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}

                    = 3003*0.75^{10} *0.25^{5} = 0.1651

(c) Probability that 10 or 11 of the problems can be resolved today is given by = P(X = 10) + P(X = 11)

    = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}

    = 3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4} = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

    given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)  

= \binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}

= 1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}

= 0.6865

3 0
3 years ago
A biology class examined some flowers in a local meadow. Out of the 40 flowers they saw, 8 were perennials. What percentage of t
Sladkaya [172]
So first we want to say, 8 out of the 40 flowers were perennials.

8 out of 40 is 8/40, or simplified down to 1/5.

1/5 in percentage form is 20% because 1 divided by 5 = 20%.
4 0
3 years ago
i kind of know its C need 2nd opinion A tire manufacturer took a random sample of 50 tires and found that 3 were defective. In a
den301095 [7]

It's kind of not C.

Solve this proportion for 'x':

                                    3/50 = x/2400

Hint: Cross-multiply the proportion, then do what you need to do.

6 0
3 years ago
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