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horsena [70]
3 years ago
6

Determine the area under the standard normal curve that lies to the left of ​(a) upper z equals 0.02 comma ​(b) upper z equals n

egative 0.19​, ​(c) upper z equals negative 0.38​, and ​(d) upper z equals negative 1.74

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0
A) 0.50798
b) 0.42465
c) 0.35197
d) 0.040930

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To solve y and x, I am adding a picture
Viktor [21]

Answer:

x =\sqrt 5

y = \sqrt{5

Step-by-step explanation:

Given

The attached triangle

Required

Solve for x

Considering angle 45 degrees, we have:

\cos(45) = \frac{y}{\sqrt{10}} --- cosine formula i.e. adj/hyp

Solve for y

y = \sqrt{10} * \cos(45)

In radical form, we have:

y = \sqrt{10} * \frac{1}{\sqrt 2}

y = \sqrt{10/2}

y = \sqrt{5

To solve for x, we make use of Pythagoras theorem

x^2 + y^2 = (\sqrt{10})^2

x^2 + y^2 =10

Substitute for y

x^2 + (\sqrt 5)^2 =10

x^2 + 5 =10

Collect like terms

x^2  =10-5

x^2=   5

Solve for x

x =\sqrt 5

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3 years ago
Carl went to the store to buy items for his party.He bought two packs for plates for $3.24 and a pack of cups for $5.70. He also
Andre45 [30]

3.24 + 5.70 + 6.17 = 15.11

20.00 - 15.11 = 5.11

He got 5.11$ of change back.

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A variable needs to be eliminated to solve the system of equations below. Choose the
notsponge [240]

Answer:

x=-2

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Step-by-step explanation:

Given data

10x – 2y = -36-----------1

7x – 2y = -30--------------2

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3x-0= -6

3x= -6

x= -6/3

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Put x= -2 in

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-14-2y=-30

-14+30=2y

16=2y

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Use Lagrange multipliers to find the volume of the largest rectangular box in the first octant with three faces in the coordinat
tensa zangetsu [6.8K]

Answer:

The volume of the largest rectangular box (V) = 81/4

Step-by-step explanation:

<u>Step 1</u>:-

Given volume of the largest rectangular box in the first octant

V = l b h

let (x ,y, z) be the one vertex in the given plane

V = f(x, y, z) = x y z

given plane.   Ф (x, y, z) = x + 9y + 4z = 27 ........(1)

<u>Step( ii):</u>

By using  Lagrange multipliers

Suppose it is required to find the extreme for the function f(x, y, z) subject to the condition Ф (x, y, z) =0

Form Lagrange function F(x, y, z) = f(x, y, z) + λ  Ф (x, y, z) where λ is called the Lagrange multipliers

F(x, y, z) = x y z+ λ ( x + 9y + 4z - 27) ......(2)

Obtain the equations are δ F / δ x = 0

                                  δ f / δ x +λ  δ Ф  / δ x =0

                           ⇒ y z + λ ( 1) = 0

                          ⇒ y z = - λ ......(a)

Obtain the equations are δ F / δ y = 0

                            δ f / δ x +λ  δ Ф  / δ x =0

                        ⇒ x z + λ ( 9) = 0

                        ⇒ \frac{xz}{9} = - λ .......(b)

Obtain the equations are δ F / δ z = 0

                                  δ f / δ x +λ  δ Ф  / δ z =0

                                   x y + λ ( 4) = 0

                                    ⇒ \frac{xy}{4} = - λ .......(c)

<u>Step (iii):-</u>

Equating (a) and (b) equations

we get         y z = \frac{xz}{9}

cancel 'z' value we get  x = 9y  .......(d)

Equating (b) and (c) equations

we get     \frac{xy}{4}  = \frac{xz}{9}

cancel 'x' value on both sides , we get

              4z =9y  ......(e)

substitute (d) (e) values in equation (1)  we get

x + 9y + 4z -27 = 0

9y + 9y + 9y -27 =0

27y -27 =0

<u> y = 1</u>

substitute y =1 in x = 9y

<u>x = 9</u>

substitute y =1 in 4z =9y

<u>z = 9 /4</u>

therefore the dimensions are x =9 , y=1 and z = 9 /4

<u>Conclusion</u>:-

The largest volume of the rectangular box V = x y z

substitute x =9 , y=1 and z = 9 /4

V = 9(1)(9/4) =81/4

The largest volume of the rectangular box (V) = 81/4

Verification :-

Given plane x + 9y + 4z = 27

substitute x =9 , y=1 and z = 9 /4

              9 + 9 + 4(9/4) = 27

           27 =27

so satisfied equation

     

3 0
3 years ago
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