Answer:
50 i think but i'm not 100 % sure i'm sorry
Step-by-step explanation:
The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
Angle BDC is given as 38° but not drawn in the figure. Amateurs.
We calculate angle DBC
DBC = 180° - 96° - 38° = 180° - 134°
We won't bother subtracting because we're really after
angle ABD = 180° - DBC = 134°
Now we have a Law of Cosines situation,
AD² = AB² + BD² - 2(AB)(BD) cos ABD
AD = √( 5.8² + 27.3² - 2(5.8)(27.3) cos 134°)
AD ≈ 31.61 m
Answer: 31.6 m
Answer:
For the 6 rows of 4 blocks the answer is 24, for the 4 rows of 4 blocks the answer is 16. Then you do 24x16.
Step-by-step explanation:
6 rows of 4 blocks = 6x4=24
4 rows of 4 blocks= 4x4=16
24
x16
___
124
+ 240
_____
364
So, your answer would be 346 cu in.!! Sorry if I'm wrong!! :(
Let the numbers be a and b, then ab=0.2 and a/b=0.8, so a=0.8b. Therefore, 0.8b^2=0.2 and b^2=0.2/0.8=2/8=1/4 and b=+1/2 or +0.5 and a=+0.8*0.5=+<span>0.4. The two numbers are therefore 0.5 and 0.4 or -0.5 and -0.4. The quotient is 0.4/0.5</span>