
Any odd number can be represented with 2n+1 where n is a whole number. Also, since the next consecutive number will be even (2n+1+1), then the next consecutive odd number must be 2n+1+2, or 2n+3. Since consecutive odd numbers are separated by 2, then the previous odd number should be 2n-1. So:
<h3>2n-1+2n+1+2n+3=36</h3><h3>6n+3=36</h3><h3>6n+3-3=36-3</h3><h3>6n/3=33/3</h3><h3>2n=11</h3>
Now in order to find three odd consecutive numbers that will sum to 36, you must be able to divide 11 evenly by 2, and have a whole number as a result. This is impossible, so there aren't any 3 odd numbers that will sum to 36.
<h2>HOPE IT HELPS ☺️</h2>
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Answer:
ANSWER
Step-by-step explanation:
<span>i think you mean discriminant in part A
</span>
Δ=b^2-4ac=256-4*2*3=256-24=232
it is positive so it has two answers.
Part B
you can find Δ
Δ=b^2-4ac=9-4*9*(-2)=81
x1=-3+9/18=6/18=1/3
x2=-3-9/18=-12/18=-2/3