A quadratic equation is shown below: 3x2 − 16x + 2 = 0 Part A: Describe the solution(s) to the equation by just determining the
radicand. Show your work. Part B: Solve 9x2 + 3x − 2 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.
<span>i think you mean discriminant in part A
</span> Δ=b^2-4ac=256-4*2*3=256-24=232 it is positive so it has two answers. Part B you can find Δ Δ=b^2-4ac=9-4*9*(-2)=81 x1=-3+9/18=6/18=1/3 x2=-3-9/18=-12/18=-2/3
