Refer to the diagram shown below.
The volume of the container is 10 m³, therefore
x*2x*h = 10
2x²h = 10
h = 5/x² (1)
The base area is 2x² m².
The cost is $10 per m², therefore the cost of the base is
(2x²)*($10) = 20x²
The area of the sides is
2hx + 2(2xh) = 6hx = 6x*(5/x²) = 30/x m²
The cost is $6 per m², therefore the cost of the sides is
(30/x)*($6) = 180/x
The total cost is
C = 20x² + 180/x
The minimum cost is determined by C' = 0.
That is,
40x - 180/x² = 0
x³ = 180/40 = 4.5
x = 1.651
The second derivative of C is
C'' = 40 + 360/x³
C''(1.651) = 120 >0, so x = 1.651 m yields the minimum cost.
The total cost is
C = 20(1.651)² + 180/1.651 = $163.54
Answer: $163.54
We have that
<span> [the mean change of altitude]=[change in altitude]/[time]
</span> [the mean change of altitude]=[-370]/[7]---------------> -52.86 ft/minute
the answer is -52.86 ft/minute (<span>the negative sign means that the plane is descending</span>)
Answer:
PREACH
Step-by-step explanation:
that is so smart :)
Answer:This expression can be solve in following steps;
Step-by-step explanation:
The factors are (x+3) & (x-2)
Your answer is (x+3)
Hope this helps