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4 years ago

This is the question: Write down the equation of a circle with centre (0,0) and radius 5.

1 answer:

3 0

You almost had it right! remember the equation of a circle is
(x - h)^2 + (y - k)^2 = r^2. the center is (h,k) and r is the radius.

(x - 0)^2 + (y - 0)^2 = 5^2

x^2 + y^2 = 25 <<< your answer

hope that helps, God bless!

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pav-90 [236]

Your answer is 56 and d

8 0

2 years ago

Plz help it’s due tonight!!!

jasenka [17]

sorry

Step-by-step explanation:

4 0

3 years ago

Let f(x) = (x − 3)−2. Find all values of c in (1, 7) such that f(7) − f(1) = f '(c)(7 − 1). (Enter your answers as a comma-separ

Sidana [21]

Answer:

This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3

Step-by-step explanation:

The given function is

$f(x)=(x-3)^{-2}$

When we differentiate this function with respect to x, we get;

$f'(x)=-\frac{2}{(x-3)^3}$

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)

This implies that;

$0.06-0.25=-\frac{2}{(c-3)^3} (6)$

$-0.19=-\frac{12}{(c-3)^3}$

$(c-3)^3=\frac{-12}{-0.19}$

$(c-3)^3=63.15789$

$c-3=\sqrt[3]{63.15789}$

$c=3+\sqrt[3]{63.15789}$

$c=6.98$

If this function satisfies the Mean Value Theorem, then f must be continuous on [1,7] and differentiable on (1,7).

But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.

3 0

3 years ago

A meeting on an unpopular topic has been announced. The number of attendees may be modeled by X where What is the probability th

krok68 [10]

Answer:

The probability that at least 5 people attend the meeting given that at least 2 attend is 12.50%.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

A meeting on an unpopular topic has been announced. The number of attendees may be modeled by X where:

P(X = x) = 1 / 2^(x+1), for x = 0,1,2,...

What is the probability that at least 5 people attend the meeting given that at least 2 attend?

The explanation of the answer is now provided as follows:

Given:

P(X = x) = 1 / 2^(x+1), for x = 0,1,2,... (1)

Since it is given that at least 2 attend, it implies that we need to calculate P(x) at x = 2.

Substituting x = 2 into equation (1), we have:

P(X = 2) = 1 / 2^(2 + 1)

P(X = 2) = 1 / 2^3

P(X = 2) = 1 / 8

P(X = 2) = 0.1250, or 12.50%

Therefore, is the probability that at least 5 people attend the meeting given that at least 2 attend is 12.50%.

7 0

3 years ago

Which statement is true?

dusya [7]

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Symmetry,

Option A.) is correct,

=> N has only the Rotational Symmetry.

7 0

3 years ago