Answer:
1
+
sec
2
(
x
)
sin
2
(
x
)
=
sec
2
(
x
)
Start on the left side.
1
+
sec
2
(
x
)
sin
2
(
x
)
Convert to sines and cosines.
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1
+
1
cos
2
(
x
)
sin
2
(
x
)
Write
sin
2
(
x
)
as a fraction with denominator
1
.
1
+
1
cos
2
(
x
)
⋅
sin
2
(
x
)
1
Combine.
1
+
1
sin
2
(
x
)
cos
2
(
x
)
⋅
1
Multiply
sin
(
x
)
2
by
1
.
1
+
sin
2
(
x
)
cos
2
(
x
)
⋅
1
Multiply
cos
(
x
)
2
by
1
.
1
+
sin
2
(
x
)
cos
2
(
x
)
Apply Pythagorean identity in reverse.
1
+
1
−
cos
2
(
x
)
cos
2
(
x
)
Simplify.
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1
cos
2
(
x
)
Now consider the right side of the equation.
sec
2
(
x
)
Convert to sines and cosines.
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1
2
cos
2
(
x
)
One to any power is one.
1
cos
2
(
x
)
Because the two sides have been shown to be equivalent, the equation is an identity.
1
+
sec
2
(
x
)
sin
2
(
x
)
=
sec
2
(
x
)
is an identity
Step-by-step explanation:
<h3>
Answer: Choice A</h3>
y axis, x axis, y axis, x axis
============================
Explanation:
Reflecting an object over the y axis twice will have it end up in its starting position. The same can be said for the x axis as well. It doesn't matter that the x axis reflections aren't grouped next to each other, nor the y. So in a sense, two x axis reflections undo each other, so do the y axis reflections, and we end up with the same image as shown in the diagram.
Answer:
Taater is a good friend of mine.
Step-by-step explanation:
The answer would be the third option, hope I'm just as helpful in times of need if its possible to subtract those then it's 100% the first option. Sorry don't exactly know this, so I'm at least trying to help.
