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Hitman42 [59]
3 years ago
12

Write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3. Include all

of your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution
Mathematics
2 answers:
jeka943 years ago
4 0

ANSWER

y-1= \frac{1}{3} (x- 6)

EXPLANATION

We want to write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3.

The slope of this line is negative reciprocal of -3.

m =  -  \frac{1}{ - 3}  =  \frac{1}{3}

The point-slope form is given by:

y-y_1=m(x-x_1)

We substitute the point and the slope to get;

y-1= \frac{1}{3} (x- 6)

photoshop1234 [79]3 years ago
4 0

Answer:

y - 1 = 1/3*(x - 6)

Step-by-step explanation:

point-slope form of a line:

y - y1 = m*(x - x1)

where x1 and y1 are the coordinates of the point included in the line and m is its slope.

Two lines are perpendicular when the multiplication of their slopes is equal to -1. In this case,

m*(-3) = -1  

m = 1/3

Replacing this slope and the coordinates of point (6, 1) we get:

y - 1 = 1/3*(x - 6)

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3 years ago
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dusya [7]

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<u>Step-by-step explanation:</u>

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Answer:  x = 0

<u>Step-by-step explanation:</u>

3^{2x}+3^{x+1}-4=0\\\\3^{2x}+3^x\cdot3^1-4=0\\\\\text{Let u = }3^x\\u^2+3u-4=0\\\\(u+4)(u-1)=0\\\\u+4=0\quad and\quad u-1=0\\u=-4\qquad and\quad u=1\\\\\text{Substitute u with }3^x\\3^x=-4\qquad and\quad 3^x=1\\\text{not possible}\ and\quad 3^x=3^0\\.\qquad \qquad \qquad \qquad \boxed{x=0}

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Answer:  No Solution

<u>Step-by-step explanation:</u>

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Answer:  No Solution

<u>Step-by-step explanation:</u>

<u>9^x=3^x-6\\\\3\cdot 3^x=1\cdot 3^x-6\\\\\text{Let u = }3^x\\\\3u=u-6\\2u=-6\\u=-3\\\\\text{Substitute u with }3^x\\3^x=-3\\\text{not possible}</u>

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6 0
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shepuryov [24]

Answer:

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Step-by-step explanation:

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The area of the triangle is the product of these:

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Answer:

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Step-by-step explanation:

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