Just apply the Pythagoras Theorem,
LN² = LM² + MN²
LN² = 7² + 8²
LN² = 49 + 64
LN = √113
In short, Your Answer would be: Option D
Hope this helps!
Y+6=(3/2)*x-6
-(3/2)x+y=-12
(3/2)x-y=12
3x-2y=24
Answer: x = 2
<u>Step-by-step explanation:</u>

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Answer: x = 0
<u>Step-by-step explanation:</u>

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Answer: No Solution
<u>Step-by-step explanation:</u>

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Answer: No Solution
<u>Step-by-step explanation:</u>
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Answer:
AKPOS/ACGF = 28√3 -48 ≈ 0.497423
Step-by-step explanation:
Let's assume the square is a unit square. Then the height of the triangle is ...
1 +(√3)/2 = h
and half the base of the triangle is ...
h/√3 = (√3)/3 +1/2 = b/2
The area of the triangle is the product of these:
A = (1/2)bh
= (2 +√3)/2 × (3 +2√3)/6
= (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12
So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...
(square area)/(triangle area) = 12/(12+7√3)
(square area)/(triangle area) = 28√3 -48
Answer:
2 5/8 - 6 1/4 + 8 1/2\
=
227
/8
Step-by-step explanation:
hope this helps :)