All categories

2 years ago

Estimate the product of -3.33 and 0.199 using the compatible numbers -3 and 0.2. Find the exact product of -3.33(0.199).

Mathematics

2 answers:

nydimaria [60]2 years ago

8 0

Answer:

-0.66267

Your. Welcome

posledela2 years ago

6 0

Answer:

-0.6

-0.66267

Step-by-step explanation:

Estimating the product :

Using compatible number :

-3 * 0.2

__ 0.2

* ___-3

______

_ - 0.6

______

-3 * 0.2 = 0.6

The exact product :

-3.33(0.199).

Using calculator :

-3.33(0.199) = - 0.66267

You might be interested in

Luisa recorded her dog’s weight, in kilograms, each week for 9 wk.

svp [43]

In order to find the median weight we must arrange the given values in an ascending order and take the middle one. Doing so lets us see that the dog's median weight was 4.8 kg.

3 0

2 years ago

Plzzzzzz helpppppp plzzz

klemol [59]

Answer:

D. 6

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

PLEASE HELP What is the value of x?

KonstantinChe [14]

Side JL is 4√2 recall that in a 30-60-90 right triangle the hypotenuse is 2 times the size of the short leg.

JL also serves as the hypotenuse of the 45-45-90 triangle JML. The ratio of side lengths in this triangle is 1:1:√2

So we can see that the value of x = 4

7 0

2 years ago

What is the correct method to label a segment with endpoint E and endpoint F?

Degger [83]

Answer : option B

the correct method to label a segment with endpoint E and endpoint F

The endpoints of the line are E and F

The Line starts at E and ends at F. The line will not extend after F

The line having end points are called as line segment

We represent a line segment by putting a line at the top

to label a segment with endpoint E and endpoint F, we use EF or FE and a line at the top

So answer is option B

4 0

3 years ago

Read 2 more answers

WHAT IS X³-27 SIMPLIFIED

Eduardwww [97]

Answer:

It is (x - 3)³ - 9x(3 - x)

Step-by-step explanation:

Express 27 in terms of cubes, 27 = 3³:

$= {x}^{3} - {3}^{3}$

From trinomial expansion:

${(x - y)}^{3} = (x - y)(x - y)(x - y) \\$

open first two brackets to get a quadratic equation:

${(x - y)}^{3} = ( {x}^{2} - 2xy + {y}^{2} )(x - y)$

expand further:

${(x - y)}^{3} = {x}^{3} - y {x}^{2} - 2y {x}^{2} + 2x {y}^{2} + x {y}^{2} - {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3x {y}^{2} - 3y {x}^{2} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3xy(y - x) \\ \\ { \boxed{( {x}^{3} - {y}^{3} ) = {(x - y)}^{3} - 3xy(y - x)}}$

take y to be 3, then substitute:

$( {x}^{3} - 3^3) = {(x - 3)}^{3} - 9x(3 - x)$

5 0

2 years ago