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Ksenya-84 [330]
3 years ago
10

What is the solution to the system of equations?

Mathematics
1 answer:
Kazeer [188]3 years ago
5 0

Answer:

C. (4 , –1)

Step-by-step explanation:

<h2>—Math</h2>

x + y = 3

y = x –5

...........

<h3>eliminate y</h3>

x + y = 3

–x + y = –5

__________–

2x = 8

x = 4

x + y = 3

4 + y = 3

y = 3 –4

y = –1

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1.0315 x 10^ written in standard notation
Katyanochek1 [597]

Answer:

10.315

Step-by-step explanation:

7 0
3 years ago
The number 0.14356712341… never repeats or terminates. The number is number. Rounded to the nearest thousandth, it is
Alenkinab [10]
0.144 because the number after 3 is 5 and that rounds the 3 to a 4.
3 0
3 years ago
Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f
masya89 [10]

Answer:

A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative  

Step-by-step explanation:

Given a function f(x), we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value "x_1" to another "x_2".

The rate of change of f(x) between x_1 and x_2 can be calculated as follows:

Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)

For:

f(x)=x^2-2x+4

Let's find f(x_1) and f(x_2), where:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7

So:

Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative

And for:

f(x)-3x+2

Let's find f(x_1) and f(x_2), where:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

So:

Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative

<em>Translation:</em>

Dada una función f(x), llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor "x_1" a otro "x_2".

La tasa de variación de f(x) entre x_1 y x_2, puede ser calculada de la siguiente forma:

Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)

Para:

f(x)=x^2-2x+4

Encontremos f(x_1) y f(x_2), donde:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

Entonces:

Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa

Y para:

f(x)-3x+2

Encontremos f(x_1) y f(x_2), donde:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

Entonces:

Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa

8 0
3 years ago
The groundhog population of​ Punxsutawny, Pennsylvania is closely monitored each year. Two years ago the population decreased by
kap26 [50]

Answer:

There was a increase of 1.7% over these three​ years

Step-by-step explanation:

Multipliers:

For a decrease of a%, we multiply by: \frac{100-a}{100}

For a increase of a%, we multiply by: \frac{100+a}{100}

What was the percentage​ increase/decrease of groundhogs over these three​ years?

Decrease of 12%(multiplication by 0.88).

Increase of 6%(multiplication by 1.06).

Increase of 9%(multiplication by 1.09).

After these three years:

0.88*1.06*1.09 = 1.017

1.017 - 1 = 0.017

0.017*100% = 1.7%

There was a increase of 1.7% over these three​ years

3 0
3 years ago
Please help me. I have an idea of what the answer might be but I’m not sure so I need you to help me clarify if I was correct so
Gemiola [76]

Hello!

<em>According to the diagram, your answer is</em> <em>D.) Some Elephants have tusks</em>

If the entire circle labeled "Elephants" was inside the circle labeled "Animals With Tusks," it would be A, but that is not the case. only part of it is inside. so D is the correct answer.

I hope this helps, and have a nice day!

8 0
3 years ago
Read 2 more answers
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