For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s
Perimeter = 2base + 2base
82 - 2(32) = 18 : 2 = 9
area = 9*32 = 288mm^2
The correct answer is B. -2x-6
Answer:
4x² -3y
Step-by-step explanation: