For simple interest, just multiply all of them together
note that 2% = 0.02
570(0.02)(4) = 45.6
simple interest is 45.6
oh and if you need the equation, it is p(r)t, or principle x rate x time
hope this helps
Answer:
The equation that models the situation is 
.
Step-by-step explanation:
Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:
(1)
Where:
, 
- Initial and final position of the softball, measured in feet.
- Acceleration, measured in meters per square second.
, 
- Initial and final velocities of the softball, measured in feet per second.
If we know that 
, 
and 
, then the equation that models the situation is:
Then, we clear the final position of the softball:
The equation that models the situation is .
Answer:
i need more information like how much mai biked
Step-by-step explanation:
Answer:
45
Step-by-step explanation:
Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.
m<EYL = (1/2)(m(arc)EVL - m(arc)EHL) Eq. 1
The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.
m(arc)EVL + m(arc)EHL = 360
m(arc)EVL = 360 - m(arc)EHL Eq. 2
We are given this:
m<EYL = (1/3)m(arc)EHL Eq. 3
Substitute equations 2 and 3 into equation 1.
(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]
Now we have a single unknown, m(arc)EHL, so we solve for it.
2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]
2m(arc)EHL = 1080 - 6m(arc)EHL
8m(arc)EHL = 1080
m(arc)EHL = 135
Substitute the arc measure just found in Equation 3.
m<EYL = (1/3)m(arc)EHL
m<EYL = (1/3)(135)
m<EYL = 45
Answer:
measure it bro lol
Step-by-step explanation:
