Answer:
∠RST = 40°
Explanation:
We are given that:
SQ bisects angle RST.
This means that:
∠QST = ∠QSR
2x = 3x - 10
10 = 3x - 2x
x = 10
Therefore:
∠QST = 2x = 2(10) = 20°
∠QSR = 3x - 10 = 3(10) - 10 = 30 - 10 = 20°
Note that both angles are equal.
Now, we can get ∠RST as follows:
∠RST = ∠QST + ∠QSR
∠RST = 20 + 20 = 40°
Hope this helps :)
Answer:
umm you have to give us more info
Step-by-step explanation:
without info we can not properly answer the question
11.5 because the formula is V=a³
Step-by-step explanation:
2^(2x) - 5(2^x) = -4
(2^x)^2 - 5(2^x) = -4
Substitute 2^x = z --> x = ln(z)/ln(2)
z^2 - 5z = -4
z^2 - 5z + 4 = 0
(z - 1)(z - 4) = 0
z = 1 --> x = ln(1)/ln(2) = 0
z = 4 --> x = ln(4)/ln(2) = 2
We want to solve 9a² = 16a for a.
Because the a is on both sides, a good strategy is to get all the a terms on one side and set it equal to zero. Then we apply the Zero Product Property (if the product is zero then so are its pieces and Factoring.
9a² = 16a
9a² - 16a = 0 <-----subtract 16a from both sides
a (9a - 16) = 0 <-----factor the common a on the left side
a = 0 OR 9a - 16 =0 <----apply Zero Product Property
Since a = 0 is already solved we work on the other equation.
9a - 16 = 0
9a = 16 <----------- add 16 to both sides
a = 16/9 <----------- divide both sides by 9
Thus a = 0 or a = 16/9
