Ab^x
a: initial value
b: value remaining after depreciation per year (in percentage)
x: number of years that have passed
35000(0.95)^8= 23219.7151
Round to the nearest hundredth value:
About $23219.72
Let me know if you have any questions :)
A = L * W
W = L - 5
these are in inches...
length width area
10 5 50 in^2
9 4 36 "
8 3 24 "
7 2 14 "
6 1 6 "
Answer:
7.6 in
Step-by-step explanation:
c = 2πr Divide each side by 2π
r = C/2π Insert values
r = 48/(2×3.14)
r = 48/6.28
r = 7.6 in
60 blocks in 30 min
18 blocks in 9 min
Method 1
60-18 = 42
42 blocks in 21 min
Method 2
30-9 =21 min
Answer:

Step-by-step explanation:
Given
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
Required
Determine the determinant
For a two by two matrix, A such that:
![A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
The determinant |A| is:

So, in
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
The determinant is:


