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mamaluj [8]
3 years ago
12

Do these ratios form a proportion? $42 per 33 customers $28 per 22 customers yes no

Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0
No I have to have a denomination
anzhelika [568]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

\frac{42}{33} = \frac{14}{11} and \frac{28}{22} = \frac{14}{11}

Both reduce to \frac{14}{11} and form a proportion

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Daniels print shop purchased a new printer for $35,000. Each year it depreciates at rate of 5%. How much will the printer be wor
Savatey [412]
Ab^x
a: initial value
b: value remaining after depreciation per year (in percentage)
x: number of years that have passed

35000(0.95)^8= 23219.7151

Round to the nearest hundredth value:
About $23219.72

Let me know if you have any questions :)
7 0
3 years ago
The width of a rectangular painting is 5 inches shorter than it's length. Creat a table of values to include possible widths,len
Misha Larkins [42]
A = L * W
W = L - 5

                                these are in inches...
               length                width                 area
                  10                      5                       50 in^2
                  9                        4                       36   "
                  8                        3                       24   "
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6 0
4 years ago
The spoke of wheel reaches from the center of the wheel to its rim if the circumstance of the wheel is 48 inches, how long is ea
user100 [1]

Answer:

7.6 in

Step-by-step explanation:

c = 2πr       Divide each side by 2π

r = C/2π     Insert values

r = 48/(2×3.14)

r = 48/6.28

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6 0
4 years ago
Susan can run 2 city blocks per minute. she wants to run 60 blocks. how long will it take her to finish if she has already run 1
Brut [27]
60 blocks in 30 min
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60-18 = 42
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Method 2
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6 0
4 years ago
Read 2 more answers
Find the determinant of the following matrix. A =<br>-2 6<br>3 5​
Blababa [14]

Answer:

|A| = - 28

Step-by-step explanation:

Given

A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]

Required

Determine the determinant

For a two by two matrix, A such that:

A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant |A| is:

|A| = a * d - b * c

So, in

A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]

The determinant is:

|A| = -2 * 5 - 6 * 3

|A| = -10 - 18

|A| = - 28

6 0
3 years ago
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