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GrogVix [38]

Answer:

y = x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 1, thus

y = x + c ← is the partial equation

To find c substitute (5, 3) into the partial equation

3 = 5 + c ⇒ c = 3 - 5 = - 2

y = x - 2 ← equation of line

6 0

3 years ago

Can someone pleas explain what is means

kipiarov [429]

Answer:

(16, 6 )

Step-by-step explanation:

Basically you are expressing the points (dots ) in coordinate form

Locate x = 16 on the x- axis ( between 14 and 18 )

Then go vertically up to the point at (16, 6 )

5 0

3 years ago

Read 2 more answers

A recent poll of 1500 new home buyers found that 60% hired a moving company to help them move to their new home. Find the margin

Mrac [35]

Answer:

The margin of error M.O.E = 2.5%

Step-by-step explanation:

Given that;

The sample size = 1500

The sample proportion $\hat p$ = 0.60

Confidencce interval = 0.95

The level of significance ∝ = 1 - C.I

= 1 - 0.95

= 0.05

The critical value:

$Z_{\alpha/2} = Z_{0.05/2} \\ \\ Z_{0.025} = 1.96$ (From the z tables)

The margin of error is calculated by using the formula:

$M.O.E = Z_{\alpha/2} \times \sqrt{\dfrac{\hat p(1 -\hat p)}{n}}$

$M.O.E = 1.96 \times \sqrt{\dfrac{\hat 0.60(1 -0.60)}{1500}}$

$M.O.E = 1.96 \times \sqrt{\dfrac{0.24}{1500}}$

$M.O.E = 1.96 \times \sqrt{1.6 \times 10^{-4}}$

M.O.E = 0.02479

M.O.E ≅ 0.025

The margin of error M.O.E = 2.5%

8 0

3 years ago

The value of 9 in 4,934 is how many times as large as 9 in 1,290

vagabundo [1.1K]

The 9 in 4,934 is 10 times larger than the 9 in 1,290.

Meaning the answer is 10 times bigger.

7 0

4 years ago

Read 2 more answers

The manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour. (a-1) At α = .05 i

ioda

Answer:

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

Step-by-step explanation:

Explanation:-

Given sample size 'n' =16

Given the manufacturer of an airport baggage scanning machine claims it can handle an average of 560 bags per hour.

mean of the Population 'μ' = 560

Mean of the sample Χ⁻ = 538

sample standard deviation' S' = 50

Null hypothesis:H₀:μ > 560

Alternative Hypothesis:H₁ : :μ < 560 (left tailed test)

Test statistic

$t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }$

$t = \frac{538-560 }{\frac{50}{\sqrt{16} } } = -1.76$

|t| = |-1.76| = 1.76

Degrees of freedom

γ = n-1 =16-1 =15

$t_{\frac{\alpha }{2} } = t_{\frac{0.05}{2} } =t_{0.025} =2.131$

Conclusion:-

The calculated value t = 1.76 < 2.131 at 0.05 level of significance

Null hypothesis is accepted

The manufacturer’s claim is greater than 560 bags per hour

6 0

4 years ago