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kobusy [5.1K]
3 years ago
13

During a four-week period, you worked the following hours: Week 1- 36 3/8 hr; Week 2- 41 1/4 hr; Week 3- 40 1/2 hr; Week 4- 38 3

/8 hr What is the average number of hours you worked in one week?
Mathematics
1 answer:
tankabanditka [31]3 years ago
7 0
(36 3/8 + 41 1/4 + 40 1/2 + 38 3/8) / 4 = 

36 + 41 + 40 + 38 = 155
3/8 + 1/4 + 1/2 + 3/8 = 3/8 + 2/8 + 4/8 + 3/8 = 12/8 = 1 1/2
155 + 1 1/2 = 156 1/2

(156 1/2) / 4 = 
313/2 * 1/4 = 313/8 = 39 1/8 <===average is 39 1/8 per week

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2 years ago
Please help.<br> Is algebra.<br> PLEASE HELP NO LINKS OR FILES.<br> I don't want links.
alexandr1967 [171]

9514 1404 393

Answer:

  9n^4

Step-by-step explanation:

The divisor and quotient can be interchanged to find the divisor:

  \dfrac{18n^6+27n^5-36n^4}{2n^2+3n-4}=\boxed{\text{Blank 1}}

Such division is carried out by first finding the quotient of the highest-degree terms:

  \dfrac{18n^6}{2n^2}=\dfrac{18}{2}n^{6-2}=9n^4

This value is used to multiply the denominator and subtract that product from the numerator to find the new numerator. The new numerator is zero, so the value that goes in Blank 1 is ...

  9n^4

_____

The attachment shows the long division.

7 0
2 years ago
I need to find Y=Mx+b. I found M but i forgot how to find B. Help
enot [183]
Y = mx + b. This linear graph passes through A(0,50) and B(10,51)

m = (y₂-y₁)/(x₂-x₁)
m= (51-50)/10-0)
m=(1)(10)

y = (1/x) + b. To find b, you plugin the coordinates of either A or B,
say A(0,50):

50 = (1/10).(0) + b
50 = 0+b  and b= 51

Hence the equation is y =0.1x + 50


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3 years ago
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kati45 [8]
P= $48c + $17.76 hope this helps

8 0
3 years ago
Answer the following True or False:
Ilia_Sergeevich [38]

False; consider as a counterexample the function <em>f</em> : ℝ→ℝ defined by

f(x)=\begin{cases}-3&\text{for }x\neq2\\0&\text{for }x=2\end{cases}

Clearly <em>f</em> approaches -3 as <em>x</em> gets closer to -2, but neither limit from either side is equal to the function's value at <em>x</em> = 2 (that is, -3 ≠ 0), so <em>f</em> is not continuous.

4 0
2 years ago
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