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3 years ago

Find x in each triangle.

Mathematics

1 answer:

Dvinal [7]3 years ago

4 0

Answer:

Step-by-step explanation:

9 squared plus 40 squared= 41 squared

You might be interested in

a jar contains ten black buttons and six brown buttons. If nine buttons are picked at random, what is the probability that exact

Anuta_ua [19.1K]

Answer:

33.04% probability that exactly five of them are black

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the buttons are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes:

Five black buttons, from a set of 10

Four brown buttons, from a set of 6.

$D = C_{10,5}*C_{6,4} = \frac{10!}{5!(10-5)!}*\frac{6!}{4!(6-4)!} = 3780$

Total outcomes:

Nine buttons, from a set of 16.

$T = C_{16,9} = \frac{16!}{9!(16-9)!} = 11440$

Probability:

$p = \frac{D}{T} = \frac{3780}{11440} = 0.3304$

33.04% probability that exactly five of them are black

6 0

3 years ago

Please help me with the correct answer

Shkiper50 [21]

Answer:

Step-by-step explanation:

c² = a² + b²

= 8² + 6²

= 64 + 36

= 100

c² = 100

c = 10

8 0

2 years ago

Help what’s the answer

Tom [10]

The answer is 474 i believe

7 0

3 years ago

Can someone help me with this please?

11111nata11111 [884]

The perimeter is
$2(2z+3z-3)=44$
$\Rightarrow 2(5z-3)=44$
$\Rightarrow 10z-6=44$
$\Rightarrow 10z=50$
$\Rightarrow z=5$

The length of AB is
$3z-3=3(5)-3=15-3=12$

6 0

2 years ago

A box of donuts containing 6 maple bars, 3 chocolate donuts, and 3 custard filled donuts is sitting on a counter in a work offic

Svetlanka [38]

Probabilities are used to determine the chances of selecting a kind of donut from the box.

The probability that Warren eats a chocolate donut, and then a custard filled donut is 0.068

The given parameters are:

$\mathbf{Bars = 6}$

$\mathbf{Chocolate = 3}$

$\mathbf{Custard= 3}$

The total number of donuts in the box is:

$\mathbf{Total= 6 + 3 + 3}$

$\mathbf{Total= 12}$

The probability of eating a chocolate donut, and then a custard filled donut is calculated using:

$\mathbf{Pr = \frac{Chocolate}{Total}\times \frac{Custard}{Total-1}}$

So, we have:

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{12-1}}$

Simplify

$\mathbf{Pr = \frac{3}{12}\times \frac{3}{11}}$

Multiply

$\mathbf{Pr = \frac{9}{132}}$

Divide

$\mathbf{Pr = 0.068}$

Hence, the probability that Warren eats a chocolate donut, and then a custard filled donut is approximately 0.068