Answer:
95.64% probability that pledges are received within 40 days
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that pledges are received within 40 days
This is the pvalue of Z when X = 40. So
has a pvalue of 0.9564
95.64% probability that pledges are received within 40 days
Answer:
Step-by-step explanation:
The formula of an area of a rectangle:
<em>l</em><em> - length</em>
<em>w</em><em> - width</em>
We have
Substitute:
Use FOIL <em>(a + b)(c + d) = ac + ad + bc + bd</em>
<em></em><em></em>
combine like terms
Answer:
He should also have applied the exponent –3 to 4 to get 4^- 3 z^8(-3)= 4^3 z ^24 Baseline =1/64 z^24 basically the last one.
just took the test if the answer is right give thanks please and thank you.
Answer:
means the inverse function
=
Step-by-step explanation:
means the inverse function
to find an inverse function, flip the x and y variables and solve for y
f(x) = 5x^3 - 6
y = 5x^3 - 6
x = 5y^3 - 6
x + 6 = 5y^3
(x + 6)/5 = y^3
= y
Answer:
Step-by-step explanation:
Part C: (Explanation with steps)
Let the length of the swimming pool = l feet
And width of the pool = w feet
Perimeter of the pool = 2(l + w) feet
Since, perimeter of the pool = 8 feet
2(l + w) = 80
l + w = 40
l = (80 - w) -------(1)
Area of the pool = Length × width
A(w) = l × w
By substituting the value of l from equation (1)
A(w) = (80 - w) × w
A(w) = 80w - w²
To find the maximum area of the pool we will find the derivative of the function with respect to 'w' and equate it to zero.
A'(w) = 80 - 2w
(80 - 2w) = 0
w =
w = 40 feet
Therefore, for width (w) = 40 feet area of the pool will be maximum.
From equation (1),
l = 80 - 40
l = 40 feet
Therefore, maximum area of the pool = l × w
= 40 × 40
= 1600 square feet
Part A:
Function representing area of the pool,
A(w) = -w² + 80w
Part B:
Maximum area of the surface of the pool = 1600 square feet