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Studentka2010 [4]
2 years ago
12

A,B and C are the vertices of a triangle,

Mathematics
2 answers:
Harlamova29_29 [7]2 years ago
3 0
SSS (side, side, side)
irinina [24]2 years ago
3 0

Answer:

SSS (side, side, side)

hope it helps:))!!!

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The graph of y=f(x) is shown below. What are all of the read solutions of f(x) = 0?
Sveta_85 [38]

Answer:

0, -1, -3

Step-by-step explanation:

f(x) = y = height of the line plotted

if you treat the x axis as the "ground" or "floor"....you're looking for the point when the graph "hits" the "floor", meaning zero height.

3 0
3 years ago
Read 2 more answers
Can u solve the answer
pickupchik [31]

Answer:

She needs 50 ft² of wood to cover the table

Step-by-step explanation:

You need to know the formula for area of a trapezoid, which is

A = (B1 + B2)h/s     (add the bases together, multiply by the height, then divide

                                by 2)

We are given B1 = 12, B2 = 8, and h = 5, so plug them in and simplify

A = (12 + 8)(5)/2

 

    A = (20)(5)/2

       A = 100/2

         A = 50 ft²

5 0
3 years ago
At a local track meet, RCMS won 3 blue ribbons than red ribbons. They also won 7 more yellow ribbons than red ribbons. RCMS won
erma4kov [3.2K]
Let no red ribbons=x
no. Of blue ribbons=x+3
No. Of yellow ribb9ns=x+7
Totsl ribbons=28
28=x+x+3+x+7
28=3x+10
3x=28-10
3x=18
X=18/3
X=6

No .of red ribbons=6
No. Of blue ribbons=x+3=9
No. Of yellow ribbons=x+7=13
5 0
3 years ago
Can someone pls show how to do this is with explanation
Keith_Richards [23]
1m = 100 cm
0.05 m = 5cm
1 km = 10000 cm
0.00005 km = 5 cm
Yes they are equal

(Mark me the brainliest if this has helped!)
4 0
3 years ago
Find the 4th term (x-y)^12
maria [59]

Answer:

The fourth term of the expansion is -220 * x^9 * y^3

Step-by-step explanation:

Question:

Find the fourth term in (x-y)^12

Solution:

Notation: "n choose k", or combination of k objects from n objects,

C(n,k) = n! / ( k! (n-k)! )

For example, C(12,4) = 12! / (4! 8!) = 495

Using the binomial expansion formula

(a+b)^n

= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n

For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is

C(n,3)a^(n-3)b^3

=C(12,3) * x^(12-3) * (-y)^(3)

= 220*x^9*(-y)^3

= -220 * x^9 * y^3

3 0
3 years ago
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