We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer ispoint (-5,12)
see the attached figure
Part 1: Equivalent fraction=3/500
Equivalent Decimal= .006
Part 2: A and E
Answer:
(-3, 1)
The solution is the point at which both lines intersect.
This is the solution since both lines would have that point and only that ppoint in this type of problem. IN a graph where 2 lines are parralel, there is no solution as they never intersect . on a graph where the 2 lines overlap there is infinite solutions. FInally in a graph like this there is exactly one solution and it is the intersection of both lines
Step-by-step explanation:
Answer:
what table add a picture of it!
Step-by-step explanation:
Median= 3
Range= 5
Mode= 3
Mean= 4