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sleet_krkn [62]

3 years ago

15

5) Today's temperature is 10 degrees. Yesterday's temperature was -3. What is

1 answer:

Troyanec [42]3 years ago

3 0

Answer:

13

Step-by-step explanation:

10--3=

So is 13

But not sure

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How do you solve for X ax-x=c

MArishka [77]

Factor out the "x" and you'll have:
$x(a-1) =c \qquad /:(a-1) \\ x=\frac{c}{a-1} \qquad \qquad a\neq 1$

8 0

3 years ago

Numarul 4 este solutie a ecuatiei 3(x-1)=5+x

sweet-ann [11.9K]

To solve x, you would distribute the 3 to the numbers in the parenthesis. 3x-3=5+x Now you would combine like-terms which would give you: 2x=2. Now you would divide by 2 on both sides to give you x=1. I hope you understand what I did. Hope I helped you!

7 0

3 years ago

Find the exact roots of x²-2x-10=4x

BARSIC [14]

Answer:

$x = 3 - \sqrt{19} \: \: or \: \: x = 3 + \sqrt{19}$

Step-by-step explanation:

The given equation is

${x}^{2} - 2x - 10 = 4x$

We group the linear terms to get:

${x}^{2} - 2x - 4x - 10 = 0$

${x}^{2} - 6x - 10 = 0$

We compare to

$a {x}^{2} + bx + c = 0$

This means

a=1, b=-6 and c=-10

We plug in the values into the quadratic formula:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a}$

This gives us

$x = \frac{ - -6 \pm \sqrt{ {( - 6)}^{2} - 4 \times 1 \times - 10 } }{2 \times 1}$

$x = \frac{ 6 \pm \sqrt{ 36 + 40 } }{2}$

$x = \frac{ 6 \pm \sqrt{76 } }{2}$

$x = \frac{ - 6 \pm 2\sqrt{19} }{2}$

$x = 3 \pm \sqrt{19}$

The solutions are

$x =3 + \sqrt{19}$

or

$x = 3 - \sqrt{19}$

7 0

3 years ago

Which scale factors produce an expansion under a dilation of the original image?

snow_lady [41]

Answer:

The correct answer is -8 and 7

Hope you have a wonderfull day :)

6 0

4 years ago

SOMEONE HELP ME PLEASE 10 POINTS

Tamiku [17]

For number 5 : 2/7 is first, then comes 1/5, then comes 1/6.

6 0

3 years ago

Read 2 more answers