All categories

3 years ago

State the slope and y-intercept

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

3 0

-y = 3/2x + 4

To get the slope and y-intercept, your equation first needs to be in the slope-intercept form, y=mx+b.

All you have to do is get rid of the -1 in front of y. Do this by dividing both sides by -1.

y = -3/2x - 4

slope = -3/2
y-intercept = -4

You might be interested in

Make me laugh and ill make u Brainliest

fiasKO [112]

Answer:

What do you call a bommerang that won't come back?

a stick

Step-by-step explanation:

8 0

2 years ago

Length of two sides of a triangle is given as 4cm and 4cm which triangle is this

My name is Ann [436]

Answer:

isosceles triangle

Step-by-step explanation:

two equal sides. is this the question only?

6 0

2 years ago

Read 2 more answers

Find the geometric mean of 2 and 3

Sav [38]

The first step in solving this problem is taking 2 and 3 and multiplying them (2 * 3 = 6) .
Now, for the second step, we will cube it. Since there are 2 numbers, we are going to use the 2nd root (2sqrt(6)) This will give us: 4.89897948557 or 5 if you would round it. This would be the Geometric Mean.

7 0

3 years ago

Find slope of the line -12x+13y=-6

Burka [1]

Answer: 2 x - 3 y = 6 i think but let let me know if i'm wrong

7 0

2 years ago

-/2 points

Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval (-∞,∞)

Part 2) The range is the interval (-∞,1]

Step-by-step explanation:

we have

$f(x)=-x^2+14x-48$

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

The range is the interval

(-∞,k]

Find the vertex

$f(x)=-x^2+14x-48$

Factor -1 the leading coefficient

$f(x)=-(x^2-14x)-48$

Complete the square

$f(x)=-(x^2-14x+49)-48+49$

$f(x)=-(x^2-14x+49)+1$

Rewrite as perfect squares

$f(x)=-(x-7)^2+1$

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0

2 years ago