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Lady_Fox [76]
3 years ago
8

You look down at an object on the ground. If your eyes are

Mathematics
1 answer:
wolverine [178]3 years ago
3 0

Answer:

We can think of this as a triangle rectangle.

We know that you eyes are 55ft above the ground, this can be one cathetus.

We also know that you see with an angle of depression of 50°, from this angle, our known cathetus would be the opposite cathetus.

Now we want to know how far is the object from you, this would be the hypotenuse of the triangle rectangle.

So we only know one angle and the opposite cathetus to this angle, then we can use the relation:

Sin(θ) = (opposite cathetus)/(hypotenuse)

Then if we use this equation, we will get:

Sin(50°) = 55ft/hypotenuse

hypotenuse = 55ft/sin(50°) = 71.8 ft

This means that the distance between you and the object is 71.8 ft.

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Angle A is circumscribed about circle O. What is the measure of A.
wlad13 [49]

Answer:

88

Step-by-step explanation:

Sum of angles in a quadrilateral= 360 degrees

<OCA=90degrees [ tangent perpendicular to the circle.

<OBA= 90degrees =tangent perpendicular

to the circle

<OCA + <OBA +92 + <OAB= 360

90 + 90 + 92 + <OAB = 360

272 + < OAB = 360

<0AB= 360- 272 =88 degrees

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The expression (x^3 )(x^(-17) ) is equivalent to (x^n). What is the value of n?
vagabundo [1.1K]

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21

Step-by-step explanation:

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3 years ago
A rocket is shot off from a launcher. The accompanying table represents the height of the rocket at given times, where x is time
galben [10]

Answer:

The height at time of 12.1 seconds is approximately 729.2562 feet

Step-by-step explanation:

The general form of the quadratic regression equation is y = A + Bx + Cx²

The quadratic regression formula is given as follows;

B = \dfrac{S_{xy}S_{x'x'}-S_{x'y}S_{xx'}}{S_{xx}S_{x'x'} -(S_{xx'})^2}

C = \dfrac{S_{x'y}S_{xx}-S_{xy}S_{xx'}}{S_{xx}S_{x'x'} -(S_{xx'})^2}

A = \bar y - B \bar x - C \bar {x^2}

S_{xx} = \Sigma (x_i - \bar x)^2

S_{xy} = \Sigma (x_i - \bar x)(y_i - \bar y)

S_{xx'} = \Sigma (x_i - \bar x)(x^2_i - \bar {x^2})

S_{x'x'} = \Sigma (x^2_i - \bar {x^2})^2

S_{x'y} = \Sigma (x^2_i - \bar {x^2})(y_i - \bar {y})

Solving using an online quadratic regression calculator, gives;

A = 2.5643259

B = 246.6374865

C = -15.41986006

Substituting gives;

y = 2.5643259 + 246.6374865·x -15.41986006·x²

When time, x = 12.1, we have;

y = 2.5643259 + 246.6374865×12.1 -15.41986006×12.1²≈ 729.2562 feet

The height at time of 12.1 seconds ≈ 729.2562 feet.

8 0
3 years ago
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