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julia-pushkina [17]
2 years ago
11

What does the slope of a speed vs time graph means

Physics
1 answer:
Agata [3.3K]2 years ago
3 0

Answer:

speed = m/s on y axis

time = s on x axis

when you calculate the slope you do y2-y1/x2-x1 right?

m/s/s become m/s^2, which is the unit of acceleration

On a speed vs time graph, if you see that the line is constant, then acceleration = 0 because there is no difference in speed, you are not acceleration or decelerating.

So in summary, it's acceleration

Hope that that answers your question

Don't hesitate to leave a comment if you are confused about something

Explanation:

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A car slows down at -5.00 m/s² until it comes to a stop after travelling 15.0 m. What was the initial speed of the car?
lapo4ka [179]
<h2>Answer: 12.24m/s</h2>

According to <u>kinematics</u> this situation is described as a uniformly accelerated rectilinear motion. This means the acceleration while the car is in motion is constant.

Now, among the equations related to this type of motion we have the following that relates the velocity with the acceleration and the distance traveled:

V_{f}^{2}-V_{o}^{2}=2.a.d   (1)

Where:

V_{f} is the Final Velocity of the car. We are told "the car comes to a stop after travelling", this means it is 0.

V_{o} is the Initial Velocity, the value we want to find

a is the constant acceleration of the car (the negative sign means the car is decelerating)

d is the distance traveled by the car

Now, let's substitute the known values in equation (1) and find V_{o}:

0-V_{o}^{2}=2(-5m/{s}^{2})(15m)    (2)

-V_{o}^{2}=-150{m}^{2}/{s}^{2}    (3)

Multiplying by -1 on both sides of the equation:

V_{o}^{2}=150{m}^{2}/{s}^{2}    (4)

V_{o}=\sqrt{150{m}^{2}/{s}^{2}}    (5)

Finally:

V_{o}=12.24m/s >>>This is the Initial velocity of the car

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yawa3891 [41]
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Ce unitate de masura are indicele de REFRACTIE?
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Explanation:

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Pls help it's due today​
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Answer:

Breh seriously. Ugh fine.

1.B

2.D

3.C

4.C

5.D,A and B

6.A,C and D

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