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1 year ago

What does the slope of a speed vs time graph means

Physics

1 answer:

Agata [3.3K]1 year ago

3 0

Answer:

speed = m/s on y axis

time = s on x axis

when you calculate the slope you do y2-y1/x2-x1 right?

m/s/s become $m/s^2$ , which is the unit of acceleration

On a speed vs time graph, if you see that the line is constant, then acceleration = 0 because there is no difference in speed, you are not acceleration or decelerating.

So in summary, it's acceleration

Hope that that answers your question

Don't hesitate to leave a comment if you are confused about something

Explanation:

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2 years ago

Read 2 more answers

Two resistors have resistances R(smaller) and R(larger), where R(smaller) < R(larger). When the resistors are connected in se

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Answer:

R = 9.85 ohm , r = 0.85 ohm

Explanation:

Let the two resistances by r and R.

when they are connected in series:

V = 12 V

i = 1.12 A

The equivalent resistance when they are connected in series is

Rs = r + R

So, By using Ohm's law

V = i Rs

Rs = V / i = 12 / 1.12 = 10.7 ohm

R + r = 10.7 ohm .... (1)

When they are connected in parallel:

V = 12 V

i = 9.39 A

The equivalent resistance when they are connected in parallel

$R_{p}=\frac{R+r}{rR}$

So, By using Ohm's law

V = i Rp

Rp = V / i = 12 / 9.39 = 1.28 ohm

$\frac{R+r}{rR}=1.28$ .... (2)

by substituting the value of R + r from equation (1) in equation (2), we get

r R = 8.36 ..... (3)

$R-r = \sqrt{\left ( R+r \right )^{2}-4rR}$

$R-r = \sqrt{\left ( 10.7 \right )^{2}-4\times 8.36}=9$ ..... (4)

By solvng equation (1) and (4), we get

R = 9.85 ohm , r = 0.85 ohm

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Answer:

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Explanation:

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2 years ago

A jet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of th

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Answer:

The radius of the curve is 9,183.67 m.

Explanation:

Given;

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acceleration of the jet plane, a = 4g = 4 x 9.8 m/s² = 39.2 m/s²

The radius of the curve is calculated from centripetal acceleration formula as given below;

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Answer:

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Explanation:

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