Answer:
44.3 m/s
Explanation:
Given that a ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release.
What is the magnitude of its velocity just before it strikes the ground ?
The parameters given are:
Height H = 100m
Since the ball is thrown from a top of a building, initial velocity U = 0
Let g = 9.8m/s^2
Using third equation of motion
V^2 = U^2 + 2gH
Substitute all the parameters into the formula
V^2 = 2 × 9.8 × 100
V^2 = 200 × 9.8
V^2 = 1960
V = 44.27 m/s
Therefore, the magnitude of its velocity just before it strikes the ground is 44.3 m/s approximately
Remember the following formulas to convert temperatures between Farenheit and Celsius:
Convert all the temperatures to Celsius to compare them.
<h2>
Part a)</h2>
Convert 265ºF to Celsius:
Then, 265ºF is equal to 129.444...ºC. Then, 265ºC is higher than 265ºF.
The correct choice is option 2) 265ºC.
Part b)
Convert 370ºF to Celsius:
Then, 370ºF is equal to 187.777...ºC. Then, 200ºC is higher than 370ºF.
The correct choice is option 2) 200ºC.
Yes. If an object would be vertical, it would most likely have potential energy due to gravity.
Answer:
c. by allowing people to easily travel to distant countries
Answer:
F = 11 N
Explanation:
Given,
Mass of a block, m = 5 kg
Acceleration of the block, a = 2.2 m/s²
We need to find the force on the person's hand. Let it is F. We know that force is given by the product of mass and acceleration as follows :
F = ma
F = 5 kg × 2.2 m/s²
F = 11 N
So, the force on a person's hand is 11 N.
