Answer:
c.) 36E
Explanation:
The magnitude of the electric field is given by the expression
(1)
where k is the Coulomb's constant, q is the charge that generates the field, and d is the distance from the charge.
In this problem, we have that the magnitude of the field at a distance d is 4E, so we can rewrite the previous equation as
Now we want to determine the electric field at a distance of 
away. Substituting into (1), we find
(2)
We also know that
(3)
So combining (2) with (3), we find a relationship between the original field and the new field:
Answer:
Heat needed = 71.19 J
Explanation:
Here heat required can be calculated by the formula
H = mL
M is the mass of water and L is the latent heat of vaporization.
Mass of water, m = 31.5 g = 0.0315 kg
Latent heat of vaporization of water = 2260 kJ/kg
Substituting
H = mL = 0.0315 x 2260 = 71.19 kJ
Heat needed = 71.19 J
Answer:
Rice
Explanation:
Because I can't control eating lots of rice
Answer:
A
Explanation:
the answer would be basicly A
Answer:
3.44 rad
Explanation:
The rotational kinetic energy change of the disk is given by ΔK = 1/2I(ω² - ω₀²) where I = rotational inertia of solid sphere = MR²/2 where m = mass of solid disk = 4 kg and R = radius of solid disk = 4 m, ω₀ = initial angular speed of disk = 0 rad/s (since it starts from rest) and ω = final angular speed of disk
Since the kinetic energy is increasing at a rate of 21 J/s, the increase in kinetic energy in 3.3 s is ΔK = 21 J/s × 3.3 s = 69.3 J
So, ΔK = 1/2I(ω² - ω₀²)
Since ω₀ = 0 rad/s
ΔK = 1/2I(ω² - 0)
ΔK = 1/2Iω²
ΔK = 1/2(MR²/2)ω²
ΔK = MR²ω²/4
ω² = (4ΔK/MR²)
ω = √(4ΔK/MR²)
ω = 2√(ΔK/MR²)
Substituting the values of the variables into the equation, we have
ω = 2√(ΔK/MR²)
ω = 2√(69.3 J/( 4 kg × (4 m)²))
ω = 2√(69.3 J/[ 4 kg × 16 m²])
ω = 2√(69.3 J/64 kgm²)
ω = 2√(1.083 J/kgm²)
ω = 2 × 1.041 rad/s
ω = 2.082 rad/s
The angular displacement θ is gotten from
θ = ω₀t + 1/2αt² where ω₀ = initial angular speed = 0 rad/s (since it starts from rest), t = time of rotation = 3.3 s and α = angular acceleration = (ω - ω₀)/t = (2.082 rad/s - 0 rad/s)/3.3 s = 2.082 rad/s ÷ 3.3 s = 0.631 rad/s²
Substituting the values of the variables into the equation, we have
θ = ω₀t + 1/2αt²
θ = 0 rad/s × 3.3 s + 1/2 × 0.631 rad/s² (3.3 s)²
θ = 0 rad + 1/2 × 0.631 rad/s² × 10.89 s²
θ = 1/2 × 6.87159 rad
θ = 3.436 rad
θ ≅ 3.44 rad
