<span>Set up the long division.
</span>
<span>6|15</span>
<span>Calculate 15 ÷ 6, which is 2 with a remainder of 3.
</span>
<span>2<span>6|15</span><span>12</span>3</span>
<span>
Answer
</span>2<span> with a remainder of </span>3
<span>Answer (Mixed Fraction)
</span><span>2</span>
5 <span>Simplify </span>
<span> to </span>
<span>
</span><span>2</span>
Done
<span>Decimal Form: 2.5</span>
**THE PERSON UNDER ME IS ALSO CORRECT, THIS IS JUST ANOTHER WAY TO APPROACH RATIOS**
Explanation: Ratio seldom compares two numbers by dividing them (this depends on the problem). We are given A 16 computers and B 26 chairs. Therefore we have the formula of A/B.For example 16/26
Solving: Divide A by B: 16/26= 0.615 or 0.6
Multiple: Multiple the quotient by 100 in order to get the percentages. 0.615 x 100 = 61.5% (if you rounded 0.61, the answer would be 60%; for this problem I didnt round hence, 61.5%)
Answer: 61.5 %
Side note: I hope this helps, feel free to let me
know if you have anymore questions.
The linear function that goes through the points (2,-4) and (-4,2) is:
y = -x + 2.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
A linear function going through the points (2,-4) and (-4,2) would intersect the parabola at these points, hence these points would be the solution for the system of equations.
The slope of the line is:
m = (-4 - 2)/(2 - (-4)) = -1.
The line goes through point (2,-4), that is, when x = 2, y = -4, which we use to find the y-intercept b.
y = -x + b
-4 = -2 + b
b = -2.
Hence the equation is:
y = -x + 2.
More can be learned about linear functions at brainly.com/question/25537936
#SPJ1
f - green (A)
f' - red (B)
f'' - blue (C)
The graph of f attains local extrema at the same points that f' = 0. There's evidence of this at x = 0 and between x = 3 and x = 3.5. (At both points, curve A attains a maximum, while curve B crosses the x-axis.)
Similarly, the graph of f' attains local extrema at the same points that f'' = 0. This is seen between x = 1.5 and x = 2. (B has a max, C crosses axis)
Also, the graph of A is continuous at x = 1.5 but exhibits a sharp turn, so at this point f is not differentiable and the graph of f' (and subsequently f'') is not continuous.
