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3 years ago

How fast was a driver going if it left skid marks that were 63 feet long on wet concrete? (The coefficient of friction is 0.97)?

Mathematics

2 answers:

vredina [299]3 years ago

7 0

Answer:

Step-by-step explanation:

Assoli18 [71]3 years ago

5 0

Answer:

b 334 mph

Step-by-step explanation:

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How much is 4x+5=41

GREYUIT [131]

Answer:

x = 9

Step-by-step explanation:

4x+5=41

To solve for x, we subtract 5 from each side

4x+5-5=41-5

4x = 36

Divide each side by 4

4x/4 = 36/3

x = 9

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3 years ago

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Step-by-step explanation:

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3 years ago

2x + y + 5z = 11<br> 22x + 6y + 8z = 5 6 <br> x + 8y + 40z = 9

mafiozo [28]

Solve the following system:{2 x + y + 5 z = 11 | (equation 1)22 x + 6 y + 8 z = 56 | (equation 2)x + 8 y + 40 z = 9 | (equation 3)
Swap equation 1 with equation 2:{22 x + 6 y + 8 z = 56 | (equation 1)2 x + y + 5 z = 11 | (equation 2)x + 8 y + 40 z = 9 | (equation 3)
Subtract 1/11 × (equation 1) from equation 2:{22 x + 6 y + 8 z = 56 | (equation 1)0 x+(5 y)/11 + (47 z)/11 = 65/11 | (equation 2)x + 8 y + 40 z = 9 | (equation 3)
Divide equation 1 by 2:{11 x + 3 y + 4 z = 28 | (equation 1)0 x+(5 y)/11 + (47 z)/11 = 65/11 | (equation 2)x + 8 y + 40 z = 9 | (equation 3)
Multiply equation 2 by 11:{11 x + 3 y + 4 z = 28 | (equation 1)0 x+5 y + 47 z = 65 | (equation 2)x + 8 y + 40 z = 9 | (equation 3)
Subtract 1/11 × (equation 1) from equation 3:{11 x + 3 y + 4 z = 28 | (equation 1)0 x+5 y + 47 z = 65 | (equation 2)0 x+(85 y)/11 + (436 z)/11 = 71/11 | (equation 3)
Multiply equation 3 by 11:{11 x + 3 y + 4 z = 28 | (equation 1)0 x+5 y + 47 z = 65 | (equation 2)0 x+85 y + 436 z = 71 | (equation 3)
Swap equation 2 with equation 3:{11 x + 3 y + 4 z = 28 | (equation 1)0 x+85 y + 436 z = 71 | (equation 2)0 x+5 y + 47 z = 65 | (equation 3)
Subtract 1/17 × (equation 2) from equation 3:{11 x + 3 y + 4 z = 28 | (equation 1)0 x+85 y + 436 z = 71 | (equation 2)0 x+0 y+(363 z)/17 = 1034/17 | (equation 3)
Multiply equation 3 by 17/11:{11 x + 3 y + 4 z = 28 | (equation 1)0 x+85 y + 436 z = 71 | (equation 2)0 x+0 y+33 z = 94 | (equation 3)
Divide equation 3 by 33:{11 x + 3 y + 4 z = 28 | (equation 1)0 x+85 y + 436 z = 71 | (equation 2)0 x+0 y+z = 94/33 | (equation 3)
Subtract 436 × (equation 3) from equation 2:{11 x + 3 y + 4 z = 28 | (equation 1)0 x+85 y+0 z = (-38641)/33 | (equation 2)0 x+0 y+z = 94/33 | (equation 3)
Divide equation 2 by 85:{11 x + 3 y + 4 z = 28 | (equation 1)0 x+y+0 z = (-2273)/165 | (equation 2)0 x+0 y+z = 94/33 | (equation 3)
Subtract 3 × (equation 2) from equation 1:{11 x + 0 y+4 z = 3813/55 | (equation 1)0 x+y+0 z = -2273/165 | (equation 2)0 x+0 y+z = 94/33 | (equation 3)
Subtract 4 × (equation 3) from equation 1:{11 x+0 y+0 z = 869/15 | (equation 1)0 x+y+0 z = -2273/165 | (equation 2)0 x+0 y+z = 94/33 | (equation 3)
Divide equation 1 by 11:{x+0 y+0 z = 79/15 | (equation 1)0 x+y+0 z = -2273/165 | (equation 2)0 x+0 y+z = 94/33 | (equation 3)
Collect results:Answer: {x = 79/15 y = -2273/165 z = 94/33

Please note the { are supposed to span over all equations but it interfaces doeans allow it. Please see attachment for clarification.

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4 years ago