we are given a vector
whose
x-component is -24.5
so, ![v_x=-24.5](https://tex.z-dn.net/?f=v_x%3D-24.5)
y-component is 31.5
so, ![v_y=31.5](https://tex.z-dn.net/?f=v_y%3D31.5)
Magnitude:
we can use formula
![|v|=\sqrt{(v_x)^2+(v_y)^2}](https://tex.z-dn.net/?f=%7Cv%7C%3D%5Csqrt%7B%28v_x%29%5E2%2B%28v_y%29%5E2%7D)
we can plug values
![|v|=\sqrt{(-24.5)^2+(31.5)^2}](https://tex.z-dn.net/?f=%7Cv%7C%3D%5Csqrt%7B%28-24.5%29%5E2%2B%2831.5%29%5E2%7D)
![|v|=39.90614](https://tex.z-dn.net/?f=%7Cv%7C%3D39.90614)
Direction:
we can use direction formula
![\theta=tan^{-1}(\frac{v_y}{v_x})](https://tex.z-dn.net/?f=%5Ctheta%3Dtan%5E%7B-1%7D%28%5Cfrac%7Bv_y%7D%7Bv_x%7D%29)
now, we can plug values
![\theta=tan^{-1}(\frac{31.5}{-24.5})](https://tex.z-dn.net/?f=%5Ctheta%3Dtan%5E%7B-1%7D%28%5Cfrac%7B31.5%7D%7B-24.5%7D%29)
![\theta=180-52.12](https://tex.z-dn.net/?f=%5Ctheta%3D180-52.12)
................Answer
Answer:
y=0
Step-by-step explanation:
asymptote formula x=-b/2a
so -(-2)/2(1.5)=2/3
then you replace it for finding the other point
g(2/3)=1.5(2/3)-3=0
y=0
I’m pretty sure the answer is 10
Answer:
See below.
Step-by-step explanation:
Equation of parabola:
y = some expression in x^2
To translate the parabola vertically, substitute y with y - k.
The translation is k units vertically. If k is positive, the translation is up. If k is negative the translation is down.
Example 1:
original parabola: y = x^2 - 2x + 5
To translate it 3 units up, we need k = 3.
Substitute y with y - 5 to get
y - 3 = x^2 - 2x + 5
y = x^2 - 2x + 8 is the equation of the parabola translated 3 units up.
Example 2:
original parabola: y = 2x^2 + 4x - 6
To translate it 5 units down, we need k = -5.
Substitute y with y - (-5), or y = 5 to get
y + 5 = 2x^2 + 4x - 6
y = 2x^2 + 4x - 11
y = 2x^2 + 4x - 11 is the equation of the parabola translated 5 units down.
Answer:
a:c:b=3:4:8/5
Step-by-step explanation:
i hope this is correct