All categories

3 years ago

Multiplying and Dividing Radical Expressions

Mathematics

2 answers:

Vladimir [108]3 years ago

7 0

Answer:

The answer for the first equation is,

B. 11

The answer for the second equation is,

D.none of these.

Llana [10]3 years ago

3 0

Answer:

first question: $\sqrt[4]{110}$ (last option)

second question: 2a³b²· $\sqrt[3]{3a}$ (3rd option)

Step-by-step explanation:

1st question - follow this rule: $\sqrt[4]{m}$ · $\sqrt[4]{n}$ = $\sqrt[4]{m x n}$

2nd question: $\sqrt[3]{24a^10b^6}$ = $\sqrt[3]{2^3a^3a^3ab^3b^3}$ = 2·a·a·b·b $\sqrt[3]{3a}$ = 2a²b² $\sqrt[3]{3a}$

You might be interested in

2) 1.) 3x+3y 6 2x+2y=4

katrin [286]

Answer:

y este egal cu 1

x este egal cu un

Step-by-step explanation:

2 plus 2 egal cu patru( adica 2 ori unu plus 2 ori 1)

La fel si la cea cu 3.

Sper că te am ajutat!!!

8 0

3 years ago

Read 2 more answers

Is this correct? Help

Mkey [24]

Everything except for 4 is correct, number 4 is c.

7 0

3 years ago

Read 2 more answers

Solve the system of equations using elimination: 8x - 8y = 0 and -5x - 7y= -12.

Lena [83]

Answer:

My answers were (1,1) for both lmk if it works ;)

Step-by-step explanation:

5 0

2 years ago

-412-(-223) worked out

shutvik [7]

Answer:

-189

Step-by-step explanation:

Remember to follow the rules of signs:

- If there are two positive signs next to each other, you add:

- If there is one negative sign and one positive sign next to each other, you subtract.

- If there is two negative signs next to each other, you add:

- 412 - (-223) = -412 + 223

Subtract:

223 - 412 = -189

-189 is your answer.

5 0

3 years ago

Read 2 more answers

Solve each equation (quadratic pattern)

dusya [7]

Answer: x = 2

Step-by-step explanation:

$2^{2x}-2^x-12=0\\\\\text{Let u = }2^x\\\\u^2-u-12=0\\(u-4)(u+3)=0\\\\u-4=0\quad and\quad u+3=0\\u=4\qquad and\quad u=-3\\\\\text{Substitute u with }2^x\\2^x=4\qquad and \quad 2^x=-3\\2^x=2^2\quad and\quad \text{not possible}\\\boxed{x=2}$

********************************************************************************

Answer: x = 0

Step-by-step explanation:

$3^{2x}+3^{x+1}-4=0\\\\3^{2x}+3^x\cdot3^1-4=0\\\\\text{Let u = }3^x\\u^2+3u-4=0\\\\(u+4)(u-1)=0\\\\u+4=0\quad and\quad u-1=0\\u=-4\qquad and\quad u=1\\\\\text{Substitute u with }3^x\\3^x=-4\qquad and\quad 3^x=1\\\text{not possible}\ and\quad 3^x=3^0\\.\qquad \qquad \qquad \qquad \boxed{x=0}$

********************************************************************************

Answer: No Solution

Step-by-step explanation:

$4^x+6\cdot 2^x+8=0\\\\2\cdot 2^x+6\cdot 2^x+8=0\\\\\text{Let u = }2^x\\2u+6u+8=0\\8u+8=0\\8u=-8\\u=-1\\\\\text{Substitute u with }2^x\\2^x=-1\\\text{not possible}$

********************************************************************************

Answer: No Solution

Step-by-step explanation:

$9^x=3^x-6\\\\3\cdot 3^x=1\cdot 3^x-6\\\\\text{Let u = }3^x\\\\3u=u-6\\2u=-6\\u=-3\\\\\text{Substitute u with }3^x\\3^x=-3\\\text{not possible}$

6 0

3 years ago