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stealth61 [152]
3 years ago
5

PLSSSSSSSSSSSSSSSSSSSSSSS HELPPPPPPPPPPPP name all three if you don im not giving you brainiest but if you name one or two then

i will give you a thanks...

Mathematics
2 answers:
elena55 [62]3 years ago
4 0

There is no question for me to answer... Could you add the question and then let me know so I can answer it???

kirill115 [55]3 years ago
3 0

Answer:

a law stating that electric current is proportional to voltage and inversely proportional to resistance.

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Describe the graph of the function f(x) = 2x^3 +14x^2 +13x +6. Include the y-intercept, x-intercepts, and the shape of the graph
vovikov84 [41]

f(x) = 2x^{3} + 14x^{2} + 13x + 6

The graph is attached below.

In order to find the y-intercept, check the graph and see where it hits the y-axis, so in this case the y-intercept would be  at (0,6).

To find the x-intercept, check the graph and see where it hits the x-axis, and here it hits at x = -6.


3 0
3 years ago
Compare 8 ⋅ 107 to 2 ⋅ 104. Plz Answer 25 Points!!!
Shalnov [3]
The answer is the first row.

Explanation:

8 * 10^7 = 80,000,000 -- 2 * 10^4 = 20,000

80,000,000 divided by 20,000 = 4,000, so it is 4,000 times larger

Therefore, the first answer is correct.

Hope I helped and good luck!
3 0
4 years ago
Read 2 more answers
I need help this is due tomorrow and I have to write an essay so please help!!!
HACTEHA [7]
2.) 6k - 9
*can't see #3*
4.) -9p + 17
5.) -15b^2 - 1b + 6c
6.) -4j
4 0
3 years ago
NEED HELP ASAP PLEASE !!
Alexxandr [17]

Answer:

A, C, E

Step-by-step explanation:

The square root of 10 is approximately 3.16, which is greater than pi which is equal to about 3.14, which shows that C is correct as well. The square root of 11 is 3.31, and the square root of 5 added to the square root of 6 is equal to about 3.69, which is greater than the square root of 11.

6 0
3 years ago
Download guathmath and put it my code please it's an app with tutors it's faster! WFHUZJ
timofeeve [1]

Answer: Advertisement?

Do I need an explanation? : Y e s  I  d o

7 0
3 years ago
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