1.5-6-12n. 1-12n
2.-4+40x-35. -39+40x
3.-36x+6+6. 12-36x
4.40n-32+8n. 48n-32
5.7n-28-6. 34-7n
6.-16+20x+3x 23x-16
7. -2n-16+8. -2n-8
8.25b-25-1. 25b-26
9.-4n+15-6n. -10n+15
-1-3x+6. -3x+5
The answer looks to be C.
Answer:get a ride back to the school or take it as missing at get like 25% off. Or print the homework
Step-by-step explanation:
Answer:
The probability that a randomly selected adult is either overweight or obese is 0,688
Step-by-step explanation:
Probability that an american adult is overweight = 0,331
Probability that an american adult is obese = 0,357
Let's find the probability that an adult is either overweight or obese, that means both events are mutually exclusive. We are interested in the probability that just one event occurs, that probability is the sum of their individual probabilities
P(overweight ∪ obese) = P(overweight) + P(obese) = 0,331 + 0,357 = 0,688
If you search him up
The answer would be
B- Bottura cooks expensive meals for people in fancy restaurants
Hope this helps :)
