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pentagon [3]
3 years ago
15

A speed walker covered 4 1/2 mi in 3/4 hour. How far will he walk in 3/4 hour if he walks?

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
7 0

Given:

Consider the complete question is "A speed walker covered 4\dfrac{1}{4} mi in \dfrac{3}{4} hour. How far will he walk in 3/4 hours if he walks twice as fast?"

A speed walker covered 4\dfrac{1}{4} mi in \dfrac{3}{4} hour.

To find:

Distance covered by him if in 3/4 hour if he walks twice as fast.

Solution:

We have,

Distance=4\dfrac{1}{2}=\dfrac{9}{2}

It means a speed walker covered \dfrac{9}{2} mi in \dfrac{3}{4} hour.

If the speed is twice then he can cover double distance is same time.

Distance covered by him if in 3/4 hour if he walks twice as fast is

2\times \dfrac{9}{2}=9

Therefore, distance covered by him is 9 mi.

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in a class of 32 students the mean height of the 14 boys is 1.56 meters and the mean height of all 32 students is 1.151 meters.
Nimfa-mama [501]

Answer: Hence, Mean height of the girls is: 1.48

Step-by-step explanation: It is given that:

in a class of 32 students .

the mean height of 14 boys is 1.56 and the mean height of all 32 students is 1.515.

Since there are 14 boys in a class.

So, number of girls is equal to (32-14)=18.

The mean height of 14 boys is 1.56.

Hence the sum of height of 14 boys is= 1.56×14=21.84

Similarly mean height of 32 students is 1.515.

Hence, sum of height of 32 students=1.515×32=48.48.

Let x denote the mean height of 18 girls.

Hence, sum of height of 18 girls is: 18 x.

Now,

18x+21.84=48.48

( since sum of height of girls and boys is equal to the sum of height of all the students)

so, 18x=48.48-21.84

18 x=26.64

Hence, x=1.48

Hence, Mean height of the girls is: 1.48

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3 years ago
Factor as the product of two binomials. x^2-100=x 2 −100=
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Step-by-step explanation:

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Find the dot product of U and V <br><br> u=7i, v = -2i + 5j
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Answer:

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(7 × -2) + (5 × 0)

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