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2 years ago

Find an equivalent ratio in simplest terms: 63:49

Mathematics

2 answers:

Fudgin [204]2 years ago

4 0

Answer:Is 97.

Step-by-step explanation:

Ede4ka [16]2 years ago

3 0

I think it’s 9:7 because the GCF of 63 and 49 is 7. So, you would divide both numbers by 7 to get 9:7.

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How to know if an equation is false, true, or an open scentence

beks73 [17]

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3 years ago

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Find the area of each figure below

Ugo [173]

Answer:

25. $27a^{3}b^{2}$

26. $3\pi x^{3}y$

Step-by-step explanation:

For 25:

$A = \frac{a+b}{2} h$ (area of a trapezoid)

$A=\frac{11a^{2}b+7a^{2}b}{2} *3ab$ (substitute terms)

$= \frac{18a^{2}b}{2}*3ab$ (collect like terms)

$= 9a^{2}b*3ab$ (reduce the fraction by crossing out 2)

$= 27a^{3}b^{2}$ (calculate)

For 26:

$A=\pi r^{2}$ (equation of area of a circle)

$A=\pi (3x^{3} y)^{2}$ (enter the radius)

$= 3\pi x^{3} y$ (communtative property to reorder the terms)

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3 years ago

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ELEN [110]

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2 years ago

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The radius of the large sphere is double the radius of the small sphere. How many times is the volume of the large sphere than t

kobusy [5.1K]

The volume of a sphere is $\cfrac{4}{3}\ \pi r^3$

So, if the small sphere has radius $r$ and the largest sphere has radius $2r$ , their volumes are

$V_1 = \cfrac{4}{3}\ \pi r^3,\quad V_2 = \cfrac{4}{3}\ \pi (2r)^3 = \cfrac{4}{3}\ \pi 8r^3$

So, their ratio is

$\cfrac{V_2}{V_1} = \cfrac{\frac{4}{3}\ \pi 8r^3}{\frac{4}{3}\ \pi r^3} = 8$

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3 years ago

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PLEASE HELP ME WITH THIS!!!

Bess [88]

Answer:

I think the answer would be C

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3 years ago