let's firstly convert the mixed fractions to improper fractions and then add them up.
![\bf \stackrel{mixed}{1\frac{11}{12}}\implies \cfrac{1\cdot 12+11}{12}\implies \stackrel{improper}{\cfrac{23}{12}}~\hfill \stackrel{mixed}{1\frac{1}{3}}\implies \cfrac{1\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{4}{3}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B11%7D%7B12%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%2012%2B11%7D%7B12%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B23%7D%7B12%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%203%2B1%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \stackrel{\textit{Alex's}}{\cfrac{4}{3}}~~+~~\stackrel{\textit{more yards}}{\cfrac{23}{12}}\implies \stackrel{\textit{using an LCD of 12}}{\cfrac{(4)4~~+~~(1)23}{12}}\implies \cfrac{16+23}{12} \\\\\\ \cfrac{39}{12}\implies \stackrel{\textit{simplified}}{\cfrac{13}{4}}\implies 3\frac{1}{4}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7BAlex%27s%7D%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bmore%20yards%7D%7D%7B%5Ccfrac%7B23%7D%7B12%7D%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20an%20LCD%20of%2012%7D%7D%7B%5Ccfrac%7B%284%294~~%2B~~%281%2923%7D%7B12%7D%7D%5Cimplies%20%5Ccfrac%7B16%2B23%7D%7B12%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B39%7D%7B12%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bsimplified%7D%7D%7B%5Ccfrac%7B13%7D%7B4%7D%7D%5Cimplies%203%5Cfrac%7B1%7D%7B4%7D)
16% = 0.16
'of' = multiplication
0.16 * 140 = 22.4
Answer:
its 3 3/4 or in decimal form 3.75
Step-by-step explanation:
15 divided by 4 gives you that answer
For this case we have:
By property of the radicals: ![\sqrt {n} = n ^ {\frac {1} {2}}](https://tex.z-dn.net/?f=%5Csqrt%20%7Bn%7D%20%3D%20n%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B2%7D%7D)
Given ![3 \sqrt {27}](https://tex.z-dn.net/?f=3%20%5Csqrt%20%7B27%7D)
We can rewrite it as:
![3 \sqrt {(3 * 3 * 3)} =\\3 \sqrt {(3 ^ 2 * 3)}](https://tex.z-dn.net/?f=3%20%5Csqrt%20%7B%283%20%2A%203%20%2A%203%29%7D%20%3D%5C%5C3%20%5Csqrt%20%7B%283%20%5E%202%20%2A%203%29%7D)
We know that by property of the radicals:
, then:
![3 \sqrt {(3 ^ 2 * 3)} = 3 (\sqrt {3 ^ 2} *\sqrt {3})](https://tex.z-dn.net/?f=3%20%5Csqrt%20%7B%283%20%5E%202%20%2A%203%29%7D%20%3D%203%20%28%5Csqrt%20%7B3%20%5E%202%7D%20%2A%5Csqrt%20%7B3%7D%29)
Simplifying, considering that
, we have:
![3 * 3 * \sqrt {3} =\\9 \sqrt {3} =\\9 * (3) ^ {\frac {1} {2}}](https://tex.z-dn.net/?f=3%20%2A%203%20%2A%20%5Csqrt%20%7B3%7D%20%3D%5C%5C9%20%5Csqrt%20%7B3%7D%20%3D%5C%5C9%20%2A%20%283%29%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B2%7D%7D)
Answer:
![3 \sqrt {27} = 9 * (3) ^ {\frac {1} {2}}](https://tex.z-dn.net/?f=3%20%5Csqrt%20%7B27%7D%20%3D%209%20%2A%20%283%29%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B2%7D%7D)