3 years ago

Find the square of ( b - 9 )

Mathematics

1 answer:

Kruka [31]3 years ago

6 0

Answer:

${b}^{2} - 18b + 81$

Step-by-step explanation:

${(b - 9)}^{2} = {b}^{2} - 2 \times b \times 9 + {(9)}^{2} \\ = {b}^{2} - 18b + 81$

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