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3 years ago

14

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

e given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.
y=−16x^2+146x+137

1 answer:

Mars2501 [29]3 years ago

3 0

Answer:

10.17

Step-by-step explanation:

Given the following Quadratic equation:

The steps to solve it are:

1. Substitute into the equation:

2. Use the Quadratic formula .

In this case:

Substituting values into the Quadratic equation, you get (Round the values to the nearest hundreth):

3. The positive value is the time that the rocket will hit the ground.

Therefore, the rocket will hit the ground after .

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33.366 divided by 6.7

andrey2020 [161]

Answer:

Step-by-step explanation:

33.366/6.7= 4.98

5 0

3 years ago

The explicit rule for the arithmetic sequence shown in the graph is a↓n=9.5+2(n-1)

Virty [35]

Answer:

True.

Step-by-step explanation:

The explicit form for an arithmetic sequence is:

$a_n=a_1+d(n-1)$

where $a_1$ is the first term and $d$ is the common difference.

The common difference here is 2 because the y's are going up by 2 while the x's are going up by 1.

Yes, the common difference is the slope.

So we have d=2.

The first term is 9.5 because that is what happens when x=1.

x is n.

y is $a_n$ .

So the answer is true.

----

You can also verify by plugging in numbers for n and see if you get the outputs mentioned in the pairs given:

Let n=1:

$a_1=9.5+2(1-1)$

$a_1=9.5+2(0)$

$a_1=9.5+0$

$a_1=9.5$

Let n=2:

$a_2=9.5+2(2-1)$

$a_2=9.5+2(1)$

$a_2=9.5+2$

$a_2=11.5$

Let n=3:

$a_3=9.5+2(3-1)$

$a_3=9.5+2(2)$

$a_3=9.5+4$

$a_3=13.5$

Let n=4:

$a_4=9.5+2(4-1)$

$a_4=9.5+2(3)$

$a_4=9.5+6$

$a_4=15.5$

Let n=5:

$a_5=9.5+2(5-1)$

$a_5=9.5+2(4)$

$a_5=9.5+8$

$a_5=17.5$

Let n=6:

$a_6=9.5+2(6-1)$

$a_6=9.5+2(5)$

$a_6=9.5+10$

$a_6=19.5$

We have confirmed that we get all 6 of the mentioned points using the equation they gave.

5 0

3 years ago

I don’t get. Can I aleast get someone to explain how to do it

Nastasia [14]

You have to make the percent a decimal by moving the decimal to the left twice. then you need to multiply the other number.

5 0

4 years ago

Read 2 more answers

Solve the quadratic equation by completing the square x^2+5x-3=0

PIT_PIT [208]

${\tt{x = \frac{ -b± \sqrt{ {b}^{2} - 4ac } }{2a} }}$

${\tt{ x = \frac{ - 5±\sqrt{{5}^{2} - 4 \times 1 \times ( - 3)} }{2 \times 1} }}$

${\tt{x = \frac{ - 5±\sqrt{25 + 12} }{2} }}$

${\tt{x = \frac{ - 5 ±\sqrt{37} }{2} }}$

$\: \:$

${\tt{x = \frac{ - 5 + \sqrt{37} }{2} }}$

${\tt{x = \frac{ - 5 - \sqrt{37} }{2} }}$

8 0

3 years ago

A Tourist Information Center is between a Bus Station and a Train Station. When mapped on a grid, the Train Station is located a

galben [10]

Answer:

X = 9 and Y = 8

Step-by-step explanation:

We are to find the midpoint of the coordinates (13,15) and (5,1).

Using the midpoint formula;

M(X, Y) = [(x1+x2)/2, (y1+y2)/2]

X = (x1+x2)/2

Y = (y1+y2)/2

From the coordinates, x1 = 13, y1 = 15, x2 = 5 and y2 = 1

X = 13+5/2

X = 18/2

X = 9

Similarly;

Y = 15+1/2

Y = 16/2

Y = 8

Hence The Tourist Information Center is located at point X = 9 and Y = 8

4 0

4 years ago