Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.
y=−16x^2+146x+137

Answer 1

Answer:

10.17

Step-by-step explanation:

Given the following Quadratic equation:

The steps to solve it are:

1. Substitute  into the equation:

2. Use the Quadratic formula .

In this case:

Substituting values into the Quadratic equation, you get (Round the values to the nearest hundreth):

3. The positive value is the time that the rocket will hit the ground.

Therefore, the rocket will hit the ground after .