Answer:
-5/3
Step-by-step explanation:
-8--3=-5
5-2=3
Answer:
avn= -8 + (n-1)(-7)
Step-by-step explanation:
arithmetic sequence formula= avn= av1 + (n-1)d
av1= first number in the sequence
d= common difference
n= the number of the term to find
The common difference is -7 so d=-7 and you plug it into the equation. The first number in the sequence is -8 so av1.
There is no specific n to find so it remains n.
I hope this helps! Let me know if this helps.
Answer:
Step-by-step explanation:
All the relations are not functions. We can determine ( identify ) whether a relation is function or not by drawing a vertical line intersecting the graph of the relation. This is called vertical line test.
- If the vertical line intersects the graph of a relation at one point , the relation is a function .
- If it cuts at more than one point , it is not a function. It means that if there are more points of the graph of a relation of a vertical line , same first component ( pre - image ) has more images ( second component ) which is not the function by definition.
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Let's check all of the options :
☐ Option A :
- The vertical line cuts the graph at two points. So , the graph does not represent a function.
☐ Option B
- No! This is also not a function as the vertical line cuts the graph at two points.
☐ Option C
- Nah! This too can't be called a function as the vertical line cuts the graph at two points.
☑ Option D
- Yep! The vertical line cuts the graph at one point. Thus , the graph represents a function.
Yayy!! We found our answer. It's ' Option D '.
Hope I helped ! ツ
Have a wonderful day / night ! ♡
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1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:
A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?
You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked
2) a - 2% as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.
b - 1,000,000/2500 = 400
400 packages are defective each year
