Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
1 hour = 7/18 of the distance between two ports
Step-by-step explanation:
Given that:
In 3/7 hours distance traveled is 1/6
For finding distance in one hour, divide both sides by 7/3 so that 3/7 would be cancelled out:
3/7 * 7/3 hours = 1/6 * 7/3 distance
By simplifying:
1 hour = 7/18 of the distance between two ports
This means that in one hour 7/18 of the distance is covered between two ports.
i hope it will help you!
Answer:
B
Step-by-step explanation:
The maximum amount Eric can spend on magazines is $25 less the cost of lunch, $15.
The appropriate inequality sign would be less than since he cannot spend more than $25.
Also, the amount he can spend on magazines would be what is left after paying for lunch.
So the correct inequality is 4m - 15 < 25
Use a calculator and it would give you 1/20. Best of luck!
