Answer:
$641.91
Step-by-step explanation:
A(t) = 570(1+0.02)^6
According to the Central Limit Theorem, the distribution of the sample means is approximately normal, with the mean equal to the population mean (1.4 flaws per square yard) and standard deviation given by:

The z-score for 1.5 flaws per square yard is:

The cumulative probability for a z-score of 1.11 is 0.8665. Therefore the probability that the mean number of flaws exceeds 1.5 per square yard is
1 - 0.8665 = 0.1335.
Answer:
$33.81
Step-by-step explanation:
(3 * 2.49) + (2 * 3.19) + (4 * 4.99)
7.47 + 6.38 + 19.96 = 33.81
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Out of 5,400 raffle tickets sold at the carnival, 180 are winners. At this same rate, how many winning raffles tickets can be expected if 8,100 raffle tickets are sold? 247