Answer:
<h2>see the answers ⤵️</h2>
Step-by-step explanation:
<h3>to understand the solving steps you need to know about</h3>
<h3>adding or subtracting with redical experience is nothing but algebraic addition or subtraction</h3><h3>let's solve:</h3>
<u>(Note: this answer is assuming that the equation has to be put in slope-intercept format.)</u>
Answer:
Step-by-step explanation:
1) Let's use the point-slope formula to determine what the answer would be. To do that though, we would need two things: the slope and a point that the equation would cross through. We already have the point it would cross through, (-3,-4), based on the given information. So, in the next step, let's find the slope.
2) We know that the slope has to be parallel to the given line, 
. Remember that slopes that are parallel have the same slope - so, let's simply take the slope from the given equation. Since it's already in slope-intercept form, we know that the slope then must be 
.
3) Finally, let's put the slope we found and the x and y values from (-3, -4) into the point-slope formula and solve:
Therefore, 
is our answer. If you have any questions, please do not hesitate to ask!
The first one is equal to 4 3/5
Because we add the front and add te numerator for the battle its stay the same
The second one is 3 1/1 so it's 3 1
We jut subtrat
C. â–łADE and â–łEBA
Let's look at the available options and see what will fit SAS.
A. â–łABX and â–łEDX
* It's true that the above 2 triangles are congruent. But let's see if we can somehow make SAS fit. We know that AB and DE are congruent, but demonstrating that either angles ABX and EDX being congruent, or angles BAX and DEX being congruent is rather difficult with the information given. So let's hold off on this option and see if something easier to demonstrate occurs later.
B. â–łACD and â–łADE
* These 2 triangles are not congruent, so let's not even bother.
C. â–łADE and â–łEBA
* These 2 triangles are congruent and we already know that AB and DE are congruent. Also AE is congruent to EA, so let's look at the angles between the 2 pairs of congruent sides which would be DEA and BAE. Those two angles are also congruent since we know that the triangle ACE is an Isosceles triangle since sides CA and CE are congruent. So for triangles â–łADE and â–łEBA, we have AE self congruent to AE, Angles DAE and BEA congruent to each other, and finally, sides AB and DE congruent to each other. And that's exactly what we need to claim that triangles ADE and EBA to be congruent via the SAS postulate.
Answer: 875
Step-by-step explanation:
You can set up proportions so it’s like: 1/350=2.5/x and then solve for x
