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3 years ago

Please help me I need the answers!

Mathematics

1 answer:

Amanda [17]3 years ago

7 0

Answer:

yh dumb

Step-by-step explanation:

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What are the first 3 common multiples of 3 and 5

marshall27 [118]

The least common multiple is the smallest number that is divisible by each of the numbers being considered. Example: While 15, 30, 45, 60, 75, ... are all commonmultiplies of 3 and 5, 15 is the smallest number divisible by both 3 and 5. It is the leastcommon multiple.

5 0

3 years ago

Read 2 more answers

List the values that make up the domain of this relation.

balandron [24]

$\bf (\stackrel{\downarrow }{5},3),(\stackrel{\downarrow }{2},-7),(\stackrel{\downarrow }{1},-8),(\stackrel{\downarrow }{8},3)\qquad \quad \stackrel{\textit{the domain is always the set of the 1st coordinate}}{(5,2,1,8)}$

6 0

3 years ago

Find the 100th term in the arithmetic sequence 0,5,10,15

Viktor [21]

Answer:

easy peasy,

the 'n' th term of any arithmetic sequence can be found with the following formula

=> a + ( n-1) d, [where 'a' if the first term of the sequence, 'n' the number of term we need to find, and 'd' being the common difference between each two consecutive term of the sequence)

all in this case would be,

a = 0

n = 100

d = +5

hence the 100th term would be,

=> 0 + (100 - 1) 5

=> 99 x 5

=> 495

8 0

4 years ago

Is the given value a solution to the equation? 4(n) - 3 = -2(n) + 9 n=2

nlexa [21]

Answer:

Yes!

The solution to the equation is n = 2

Step-by-step explanation:

Given the equation

$4\left(n\right)-3=-2\left(n\right)+9$

remove the parentheses

$4n-3=-2n+9$

Add 3 to both sides

$4n-3+3=-2n+9+3$

Simplify

$4n=-2n+12$

Add 2n to both sides

$4n+2n=-2n+12+2n$

Simplify

$6n=12$

Divide both sides by 6

$\frac{6n}{6}=\frac{12}{6}$

Simplify

$n=2$

Therefore, the value of n = 2.

Hence,

Yes!

The solution to the equation is n = 2

5 0

3 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago