In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

$\sin (\theta)=\frac{3}{5}$

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

$x^2+3^2=5^2$

Solving for x, we have

$\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}$

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

$\tan (y)=\frac{12}{5}$

Describes the following triangle

Using the Pythagorean Theorem again, we have

$5^2+12^2=h^2$

Solving for h, we have

$\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}$

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

$\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}$

To calculate the sine and cosine of the sum

$\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}$

We can use the following identities

$\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}$

Using those identities in our problem, we're going to have

$\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}$

4 0

1 year ago

What is the measure of angle AOB?

Anettt [7]

Answer:

let angle AOB and angle COD be x

the it would be

x+x+110=180

2x+110=180

2x=180-110

2x=70

x=70/2

x=35 degree.

hope it will help you.

4 0

3 years ago

A pulley moves 8.67 feet of rope per minute. How many feet of rope will the pulley move in 6

lapo4ka [179]

Answer:

The answer is : 52.02 feet in 6 min

Step-by-step explanation:

you just had to multiply 8.67 by 6

and then you got the answer.

4 0

3 years ago

In the right triangle shown, m∠V=60°m, and angle UV=18 how long is UW?

Evgen [1.6K]

Answer:

Step-by-step explanation:

Check attachment for solution

So, I believed the first case is correct since it gave us one of the option, then, the answer is D.

9√3.

So, UW = 9√3

4 0

3 years ago

﻿Help me pls. Which expression shows the prime factorization of 48? 2 × 2 × 2 × 2 × 3 2 × 2 × 2 × 3 2 × 2 × 3 2 × 2 × 2 × 3 × 3

Help me pls. Which expression shows the prime factorization of 48? 2 × 2 × 2 × 2 × 3 2 × 2 × 2 × 3 2 × 2 × 3 2 × 2 × 2 × 3 × 3