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RSB [31]
3 years ago
14

8^5 = 2^2m+3 Solve m

Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

m=6

Step-by-step explanation:

<u>Exponent properties</u>:

We can use exponent property a^{b^c}=a^{(b\cdot c)} to solve this problem.

Rewrite 8 as 2^3, then apply exponent property a^{b^c}=a^{(b\cdot c)} to simplify:

2^{3^5}=2^{2m+3},\\2^{15}=2^{2m+3}

If a^b=a^c, then b=c, because of log property \log a^b=b\log a. Using this log property, you can take the log of both sides and divide by \log a to get b=c

Therefore, we have:

15=2m+3

Subtract 3 from both sides:

12=2m

Divide both sides by 6:

m=\frac{12}{2}=\boxed{6}

<u />

<u>Alternative</u>:

Given 8^5=2^{2m+3}, to move the exponent down, we'll use log properties.

Start by simplifying:

\log 32,768=2^{2m+3}

Take the log of both sides, then use log property \log a^b=b\log a to move the exponent down:

\log(32,768)=\log 2^{2m+3},\\\log (32,768)=(2m+3)\log 2

Divide both sides by \log2:

2m+3=\frac{\log (32,768)}{\log(2)}

Subtract 3 from both sides:

2m=\frac{\log (32,768)}{\log(2)}-3

Divide both sides by 2:

m=\frac{\log (32,768)}{2\log(2)}-\frac{3}{2}=\boxed{6}

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