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sergij07 [2.7K]
2 years ago
14

ALGUIEN AYUDEME POR FAVOR :( TENGO QUE ENTREGARLO EN 15 MINUTOS

Mathematics
1 answer:
Serggg [28]2 years ago
6 0
Creo que es A si no es porfavor dime.
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In which of the following cases is productive efficiency not satisfied? Assume we start at a point on the PPF between two produc
DaniilM [7]

Answer:

A. The economy switches to producing less of one product without increasing the production of the other product

Step-by-step explanation:

PPC is the graphical representation of product combinations that an economy can produce, given resources & technology. It is downward sloping because given resources & technology, production of a good can be increased  by decreasing production of other good.

It is based on assumption that resources are efficiently utilised. Points on PPC show resources efficient utilisation, Points under PPC show under utilisation, Points outside PPC are beyond country's productive capacity.

If country produces less of a good without increasing production of other goods, implying wasted resources & production below PPC. This case doesn't satisfy productive efficiency

Other cases : Producing more of a good & less of other is just re allocative movement on the PPC itself. Production point at PPF intersection with either axis implies economy is producing only the good on that axis.

In all the cases except A. satisfy the 'productive efficiency'

3 0
3 years ago
18. Describe how to plot point A(-6, 2) on a coordinate plane.
Setler79 [48]

Answer:

To plot point A, you would count over to the left six places on the x-axis. Then, count up two places on the y-axis.

8 0
2 years ago
72-12+36 divided by 3+14•8
kupik [55]

Answer:

I got 1.25

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
Celia bought a bag of 1212 goldfish for \$3$3. What is the cost of 11 goldfish?
Anvisha [2.4K]
$2.75
it would most likely be 4 goldfish for $1
7 0
3 years ago
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