What is g(x)? please help

On a coordinate grid Ming's house is located 2 blocks to the right and 5 blocks up from (0,0). Joe house is located 3 blocks to

Burka [1]

Answer:

(5, 3)

Step-by-step explanation:

Conventionally, the ordered pairs are (right, up). Then ...

Ming's = (0, 0) + (2, 5) = (2, 5)

Joe's = Ming's + (3, -2) = (2, 5) + (3, -2) = (2+3, 5-2)

Joe's = (5, 3)

3 0

3 years ago

Help please I need 5 points total. i need 2 to left of vertex. i need vertex. i need 2 to right of vertex. Please, quickly, I am

zlopas [31]

We are given with a quadratic equation which represents a Parabola , we need to find the vertex of the parabola , But let's recall that , For any quadratic equation of the form ax² + bx + c = 0 , the vertex of the parabola is given by ;

${\quad \qquad \boxed{\bf{Vertex = \left(\dfrac{-b}{2a},\dfrac{-D}{4a}\right)}}}$

Where , D = b² - 4ac (Discriminant)

Now , On comparing the given equation with ax² + bx + c , we have

⇢⇢⇢ a = 1 , b = - 10 , c = 27

Now , Calculating D ;

${:\implies \quad \sf D=(-10)^{2}-4\times 1\times 27}$

${:\implies \quad \sf D=100-108}$

${:\implies \quad \bf \therefore \quad D=-8}$

Now , Calculating the vertex ;

${:\implies \quad \sf Vertex =\bigg\{\dfrac{-(-10)}{2\times 1},\dfrac{-(-8)}{4\times 1}\bigg\}}$

${:\implies \quad \sf Vertex = \left(\dfrac{10}{2},\dfrac{8}{2}\right)}$

${:\implies \quad \bf \therefore \quad Vertex = (5,2)}$

Hence , The vertex of the parabola is at (5,2)

Note :- As the Discriminant < 0 . So , the equation will have imaginary roots .

Refer to the attachment for the graph as well .

5 0

3 years ago

Each person in random samples of 207 male and 253 female working adults living in a certain town in Canada was asked how long, i

Sergeu [11.5K]

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females (P-value=0.155).

Step-by-step explanation:

The data is:

Males n1=207 M1=31.6 s1=24.0

Females n2=253 M2=29.3 s2=24.3

This is a hypothesis test for the difference between populations means.

The claim is that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females.

Then, the null and alternative hypothesis are:

$H_0: \mu_m-\mu_f=0\\\\H_a:\mu_m-\mu_f> 0$

The significance level is 0.05.

The sample 1 (males), of size n1=207 has a mean of 31.6 and a standard deviation of 24.

The sample 2 (females), of size n2=253 has a mean of 29.3 and a standard deviation of 24.3.

The difference between sample means is Md=2.3.

$M_d=M_m-M_f=31.6-29.3=2.3$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{24^2}{207}+\dfrac{24.3^2}{253}}\\\\\\s_{M_d}=\sqrt{2.783+2.334}=\sqrt{5.117}=2.262$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_m-\mu_f)}{s_{M_d}}=\dfrac{2.3-0}{2.262}=\dfrac{2.3}{2.262}=1.017$

The degrees of freedom for this test are:

$df=n_1+n_2-1=207+253-2=458$

This test is a right-tailed test, with 458 degrees of freedom and t=1.017, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>1.017)=0.155$

As the P-value (0.155) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females.

7 0

3 years ago

what are the coordinates of the image of the point (–3, 6) after a dilation with a center of (0, 0) and scale factor of 1/3 a. (

dybincka [34]

It's gotta be C.) I'm pretty sure

3 0

3 years ago

Read 2 more answers

On January 1, 1985, Marc has the following two options for repaying a loan:

Aliun [14]

Answer:

The correct answer is